Onyango is now three times as old as his daughter and four times as old as his son. Eight years from now, Onyango’s age will be
twelve years more than the sum of the ages of his son and daughter. Find their present ages.
1 answer:
Answer:
Brainliest please
50years is their ages now
Step-by-step explanation:
<h3>use algebra</h3>
onyango= 3a
daughter= let it be a
son= he is 4 times less than his father, 3/4a
8years
8+3a+a+8+3/4a+a
a+8+3/4a+a
7/4+1 = 8/4a+8 + 12y 20= 8/4a = 40years is the father 8 years later, so his present age is 40-8
32y= father now
daughter= 1/3×32=10years
son= 1/4×32= 8yrs
add 32+10+8= 50years
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