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mamaluj [8]
3 years ago
15

The cost, C dollars, of hiring a taxi is given by the formula C=2.00+320n, where n is the number of tenths of a mile driven. Wha

t is the cost if the taxi is hired to drive 4.0 miles?
Mathematics
1 answer:
Ainat [17]3 years ago
8 0

Answer:

$14.80

Step-by-step explanation:

I'm assuming you meant to put 3.20 since $320 a mile would be ridiculous.

C(n)=2.00+3.20n

If n = 4 miles we have:

C(4)=2+3.20(4)

C(4)=2+12.80

C(4)=14.80

So the cost of the taxi is $14.80.

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3 times what gives me a sum of 24? im trying to finish my homework so please help.
Leno4ka [110]
It is not a sum, it is a product.

3 times x = 24   (write equation)
           3x = 24  (isolate x by dividing the coefficient, 3, on both sides)
           /3     /3
             x = 8    (this i your answer)

Therefore 3 times 8 gives you 24.
4 0
2 years ago
Read 2 more answers
What is the range of the following function
AleksAgata [21]

The range is the set of y.

(-4, 4) → 4

(-3, 0) → 0

(-2, 1) → 1

(-1, 3) → 3

(0, 0) → 0

(1, 5) → 5

Answer: {0, 1, 3, 4, 5}

3 0
3 years ago
What is M<3. PLEASE HELPPP
melamori03 [73]

Answer:

105 degrees

Step-by-step explanation:

The angle of a straight line is 180 degrees. Since we need to find the angle for 3, it is 180-75 which is 105 degrees.

4 0
3 years ago
If
Leno4ka [110]

Answer:

\frac{s^2-25}{(s^2+25)^2}

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given:\mathcal{L}[t \cos 5t]=(-1)F'(s) with F(s)=\mathcal{L}[\cos 5t].

Now, F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt. Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt.

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s).

Solving for F(s) on the last equation, F(s)=\frac{s}{s^2+25}, then the Laplace transform we were searching is -F'(s)=\frac{s^2-25}{(s^2+25)^2}

3 0
3 years ago
Which of the following scenarios is least likely to be modeled by a quadratic function?
vampirchik [111]
I think the answer is c purplestar1
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3 years ago
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