Ask question

Ask question

All categories

4 years ago

12

Otto used 6 cups of whole wheat flower an x cups of white flower in the recipe. What is the equation that can be used to find th

e value of y, an the constraints on the values of x an y??

1 answer:

alexgriva [62]4 years ago

5 0

Answer:

idk

Step-by-step explanation:

You might be interested in

Simplify an expression for the perimater of the equilateral triangle shown blown

abruzzese [7]

Answer:

5.25x-6

Step-by-step explanation:

6 0

3 years ago

A triangle has interior angles measuring 36° and 112°. Which triangles are similar to this triangle? Select True or False for ea

morpeh [17]

Hi there!

Since the interior measures of triangles added up always equals 180 degrees, the other interior angle of the triangle must be 32 degrees.

180 - 112 - 36 = 32

So, any triangle with interior measures that measure any angles of 36, 112, and 32 degrees are similar.

<span>triangle with interior angles measuring 36° and 32° - true
triangle with interior angles measuring 36° and 148° - false
triangle with interior angles measuring 32° and 112° - true
triangle with interior angles measuring 112° and 148 - </span>false

Hope this helps!

3 0

4 years ago

Read 2 more answers

Is abc~xyz? if so identify similarity postulate or theorem that applies?

iren [92.7K]

B. Similar -AA because the side lengths are two different lengths with angels being similar

4 0

4 years ago

Read 2 more answers

Find the area of the helicoid (or spiral ramp) with vector equation r(u, v) = ucos(v) i + usin(v) j + v k, 0 ≤ u ≤ 1, 0 ≤ v ≤ 9π

Natasha2012 [34]

Let $H$ denote the helicoid parameterized by

$\mathbb r(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+v\,\mathbf k$

for $0\le u\le1$ and $0\le v\le9\pi$ . The surface area is given by the surface integral,

$\displaystyle\iint_H\mathrm dS=\iint_H\|\mathbf r_u\times\mathbf r_v\|\,\mathrm du\,\mathrm dv$

We have

$\mathbf r_u=\dfrac{\partial\mathbf r(u,v)}{\partial u}=\cos v\,\mathbf i+\sin v\,\mathbf j$
$\mathbf r_v=\dfrac{\partial\mathbf r(u,v)}{\partial v}=-u\sin v\,\mathbf i+u\cos v\,\mathbf j+\mathbf k$
$\implies\mathbf r_u\times\mathbf r_v=\sin v\,\mathbf i-\cos v\,\mathbf j+u\,\mathbf k$
$\implies\|\mathbf r_u\times\mathbf r_v\|=\sqrt{1+u^2}$

So the area of $H$ is

$\displaystyle\iint_H\mathrm dS=\int_{v=0}^{v=9\pi}\int_{u=0}^{u=1}\sqrt{1+u^2}\,\mathrm du\,\mathrm dv$
$=\dfrac{9(\sqrt2+\sinh^{-1}(1))\pi}2$

5 0

3 years ago

Help me with the last part please

MaRussiya [10]

Answer:

A" (3,-3)

B" (4,-5)

C" (-1,-4)

Step-by-step explanation:

You already found the coordinates of A' B' C' so just use those points to do the translation.

4 0

4 years ago