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Serggg [28]
3 years ago
15

How would you make a 2.00L of 0. 500M sodium chloride solution. (assume you have a fully equipped lab with water); sketch, calc

and write a summary statement How would you male 2.0L of 0.100M sulfurice acid from a 12.0M stock bottle of sulfurice acid Cela elreab and. totomont
Chemistry
1 answer:
Gwar [14]3 years ago
5 0

Answer:

Sodium chloride solution:

First you need to calculate the mass of salt needed (done in the explanation), which is 58.44g. Then it have to be weighted in an analytical balance in a weighting boat and then transferred into a 2L volumetric flask that is going to be filled until the mark with distilled water.

Sulfuric acid dilution:

First you need to calculate the volume needed (done in the explanation), it is 16.6 mL. Using a graduated pipette one measures this volume and transfer it into a 2L volumetric flask that is already half filled with distilled water, and then one fills it until its mark.

Explanation:

Sodium chloride solution:

Each liter of a 0.500M solution has half mol, so 2L of said solution has 1 mol of salt. Sodium chloride molar mass is 58.44g/mol, so in 2L of solution there is 58.44g of salt. That`s the mass that`s going to be weighted and transferred to a 2L volumetric flask.

Sulfuric acid dilution:

This is the equation for dilution of solutions:

c_{1} v_{1} =c_{2} v_{2}

Where "c1" stands for the initial concentration (stock solution concentration), "v1" for the initial volume (volume of stock solution used), "c2" for the desired concentration and "v2" for the desired volume.

When we are diluting from a stock solution we want to know how much do we have to pipette from the stock solution into our volumetric flask. We do so by isolating the "v1" term from the dilution equation:

v_{1} =\frac{c_{2} v_{2} }{c_{1} }

in this case that would be:

v_{1} =\frac{0.100 x2.0 }{12.0 }=0.0166L=16.6mL

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Andreas93 [3]

Answer: Option (D) is the correct answer.

Explanation:

When aluminium reacts with oxygen, it results in the formation of a layer of aluminium oxide on its surface.

This outer layer gets corroded but it forms a protective coating for the inner layers that prevents from further corrosion.

Thus, we can conclude that metals like aluminum can react with oxygen to form coatings that prevent corrosion.

5 0
3 years ago
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The strength of a magnetic field follows _____.
nordsb [41]

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5 0
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What is the mass of a 1.68-l sample of a liquid that has a density of 0.921g/ml?
Gwar [14]
Hey there!

Volume in mL :

1.68 L  * 1000 => 1680 mL

Density = 0.921 g/mL

Therefore:

Mass = density * Volume

Mass = 0.921 * 1680

Mass = 1547.28 g 
7 0
3 years ago
Si se tiene 1mol de NO . cuantas moleculas de NO hay
kumpel [21]

if you have 1mol of NO. how many molecules of NO are there

Answer:

6.02 x 10²³ molecules

Explanation:

Given parameters:

Number of moles of NO = 1 mole

Unknown:

Number of molecules in NO;

Solution:

A mole of compound contains the Avogadro's number of particles.

  1 mole of a substance contains 6.02 x 10²³ molecules

So, 1 mole of NO contained 6.02 x 10²³ molecules

3 0
2 years ago
1. What amount of ammonia (in moles) is produced by the reaction of 4.00 mol H2 with 3.00 mol Nz?
ArbitrLikvidat [17]
<h2>Answer:  6 moles</h2>

<h3>Explanation:</h3>

3 H₂    +    N₂   →   2 NH₃

   ↓            ↓

4 mol       3 mol

Since the moles of N₂ is the smaller of the two reactants, then N₂ is the limiting factor (the reactant that will decide how much ammonia is produced since it has the smaller amount of moles). ∴ we have to use it in calculating the number of moles of ammonia

The mole ratio of N₂ to NH₃ based on the balanced equation is 1 to 2.

∴ the moles of NH₃ = moles of N₂ × 2

                                =  3 moles × 2

                                = 6 moles

7 0
3 years ago
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