In preparing diluted solutions from concentrated solutions we can use the following formula
c1v1 = c2v2
c1 and v1 are the concentration and volume of the concentrated solution respectively
c2 and v2 are the concentrations and volume of the diluted solution respectively
Substituting these values ,
20 mL x 1.0 M = C x 60 mL
C = 0.33 M
The concentration of the resulting diluted solutions is 0.33 M
Hey there!:
Given the reaction:
2 C2H2 + 5 O2 → 4 CO2 + 2 H2O
5 moles O2 ------------- 4 moles CO2
3.00 moles O2 ---------- ( moles of CO2 ?? )
moles of CO2 = 3.00 * 4 / 5
moles of CO2 = 12 / 5
moles of CO2 = 2.4 moles
So, molar mass CO2 = 44.01 g/mol
Therefore:
1 mole CO2 -------------- 44.01 g
2.4 moles CO2 ---------- ( mass of CO2 )
mass of CO2 = 2.4 * 44.01 / 1
mass of CO2 = 106 g
Answer A
Hope that helps!
Answer: 1 mole of H2O= about 1/3 of a cup (18 mL). It is helpful ... 6.02 x 1023 H2O molecules. = 6.02 x 1023 NaCl formula unit. 1 mole C. 1 mole H2O. 1 mole
Explanation:
Answer:
Heating this gas to 55 °C will raise its volume to 6.87 liters.
Assumption: this gas is ideal.
Explanation:
By Charles's Law, under constant pressure the volume of an ideal gas is proportional to its absolute temperature (the one in degrees Kelvins.)
Alternatively, consider the ideal gas law:
.
- is the number of moles of particles in this gas. should be constant as long as the container does not leak.
- is the ideal gas constant.
- is the pressure on the gas. The question states that the pressure on this gas is constant.
Therefore the volume of the gas is proportional to its absolute temperature.
Either way,
.
.
For the gas in this question:
- Initial volume: .
Convert the two temperatures to degrees Kelvins:
- Initial temperature: .
- Final temperature: .
Apply Charles's Law:
.
The number of protons in the nucleus for that element