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Georgia [21]
3 years ago
8

Eczema is a type of skin disease that appears as rashes or swelling. Eczema causes skin irritation or itchiness. What type of ti

ssue does eczema affect? A. nervous B. muscle C. epithelial D. connective
Chemistry
1 answer:
bixtya [17]3 years ago
5 0

Answer:

epithelial

Explanation:

nervous tissue are located only on specific areas mainly in the dermis like the parcinian to detect pressure so rashes won't be seen.muscle is located deep under the sub cutaneous layer so the symptoms can't appear.connective is also located deep in the skin eg in the eyes but epithelial tissue covers the deeper latest of the skin therefore this condition's signs can be well acknowledged I guess

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What charge would you expect for an formed by S?
sp2606 [1]

Answer:

in this the correct answer is option 2.

6 0
3 years ago
C12H26O + SO3+NaOH ----> C12H25NaSO4+ H2O
Vlad [161]

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

4 0
3 years ago
The leaves of the rhubarb plant contain high concentrations of diprotic oxalic acid (hooccooh) and must be removed before the st
Andrei [34K]
First we have to find Ka1 and Ka2
pKa1 = - log Ka1 so Ka1 = 0.059
pKa2 = - log Ka2  so Ka2 = 6.46 x 10⁻⁵
Looking at the values of equilibrium constants we can see that the first one is really big compared to second one. so, the pH will be affected mainly by the first ionization of the acid.
Oxalic acid is H₂C₂O₄
H₂C₂O₄      ⇄     H⁺   + HC₂O₄⁻
0.0356 M            0          0
0.0356 - x            x          x
Ka1 = \frac{[H^+][HC2O4^-]}{[H2C2O4]} = x² / 0.0356 - x
x = 0.025 M
pH = - log [H⁺] = - log (0.025) = 1.6
5 0
3 years ago
How many moles of lithium nitrate<br> (LINO3) are in 256 mL of a 0.855 M<br> solution?
sweet [91]

Answer:

There are 0.219 mol of LINO3

7 0
3 years ago
If 26.2 grams of a pure compound contain 8.77 × 1022 molecules, what is the molecular weight of this compound? Answer in units o
Nataly [62]

Answer:

Mw = 179.845 g/mol

Explanation:

  • Mw [=] g/mol

∴ w = 26.2 g

∴ 1 mol = 6.02 E23 molecules.......Avogadro's number

⇒N° moles = 8.77 E22 molecules * ( mol / 6.02 E23 molecules ) = 0.146 mol

⇒ Mw = 26.2 g / 0.146 mol = 179.845 g/mol

3 0
3 years ago
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