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3 years ago

A runner completes the 200-meter dash with a time of 19.80 seconds. What was the runner's average speed in miles per hour?

Physics

1 answer:

andriy [413]3 years ago

4 0

Answer:

v = 22.54 mph.

Explanation:

Given that,

Distance moved, d = 200 m

Time, t = 19.8 s

We need to find the runner's average speed.

We know that,

1 mile = 1609.34 m

200 m = 0.124 miles

19.8 seconds = 0.0055 h

So,

Speed = distance/time

$v=\dfrac{0.124}{0.0055}\\\\v=22.54\ mph$

So, the runner's average speed is 22.54 mph.

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4 years ago

A triangle ∆P QR has vertices P(3, 2, −4), Q(1, 0, −4), R(2, 1, 1). Use the distance formula to decide which one of the followin

777dan777 [17]

Answer:

a. FALSE

b.TRUE

C. FALSE

Explanation:

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$d=\sqrt{(x_{2}-x_{1})^{2} +(y_{2}-y_{1})^{2} +(z_{2}-z_{1})^{2}}\\$

hence we determine the distances between all the points

a.P(3,2,-4), Q(1,0,-4), R(2,1,1)

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For point PR

we have

$PR=\sqrt{(2-3)^{2} +(1-2)^{2} +(1-(-4))^{2}}\\PR=\sqrt{1+1+9}\\ PR=\sqrt{11}\\$

$|PQ|\neq |PR|$

B. For point RP

$RP=\sqrt{(3-2)^{2} +(2-1)^{2} +(-4-1)^{2}}\\RP=\sqrt{1+1+25}\\ RP=\sqrt{27}$

for point RQ we have

$RQ=\sqrt{(1-2)^{2} +(0-1)^{2} +(-4-1)^{2}}\\RQ=\sqrt{1+1+25}\\ RQ=\sqrt{27}$

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3 years ago

Two forces of 8N and 10N CANNOT give a resultant of a. 1 N b. 2 N c. 9 N d. 18 N

Lelechka [254]

Answer:

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3 years ago

How much GPE is stored when an 80kg astronaut climbs to the top of a 5m high lunar lander? The gravity strength on the moon is 1

8_murik_8 [283]

Answer:

The GPE, stored is 640 Joules

Explanation:

The given parameters are;

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The Gravitational Potential Energy, GPE, stored is given according to the following equation;

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6 0

3 years ago