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dalvyx [7]
3 years ago
14

A person riding a bike has an initial velocity of 2.5 m/s and accelerates at a rate of 1.5 m/s2 for

Physics
1 answer:
Dovator [93]3 years ago
6 0

Answer:

11.5m/s

Explanation:

v=2.5

a=1.5

t=6s

vf=vi+at

vf=2.5+(1.5)(6)

vf=11.5

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A mechanic pushes a 3540 kg car from rest to a speed of v, doing 4864 J of work in the process. Find the speed v. Neglect fricti
topjm [15]

Answer:

1.66 m/s

Explanation:

Work or kinetic energy = \frac{1}{2} mv^{2}

4864=\frac{1}{2} (3540)v^{2}

v = 1.66 m/s

6 0
2 years ago
A person throws a ball from height of 6 feet with an initial vertical velocity of 48 feet per second. Use the vertical motion mo
True [87]

Explanation:

Recall the equation for time is distance divided by speed. Here you can use that to solve for "t".

7 0
2 years ago
Is cracking the eggs a physical change or a chemical change and why
matrenka [14]

Answer:

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Hope it helps

3 0
2 years ago
A rope is used to pull a 4.36 kg block at constant speed 4.33 m along a horizontal floor. The force on the block from the rope i
geniusboy [140]

Answer:

Explanation:

The horizontal component of force applied = 7.97 cos 26.2 = 7.15 N.

Vertical component in upward direction = 7.97 sin 26.2 = 3.52 N.

Since the body is moving with uniform velocity, friction force will equalize the external horizontal component = 7.15 N.

So frictional force  = 7.15 N.

a) Work done by rope force per second = force in horizontal direction x displacement per second = 7.15 x 4.33 = 30.95 J

b) Increase in thermal energy per second will be due to negative work done by frictional force = work done by external force = 30.95 J.

c) Normal force acting downwards = weight - vertical component of external force  = 4.36 x 9.8 - 3.52 = 39.21 N

coefficient of friction = friction force / normal force = 7.15 / 39.21 = 0.18

4 0
3 years ago
During the first 5 seconds after a ball is dropped from rest, how far will it fall?
agasfer [191]
The answer is 125metre
5 0
3 years ago
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