1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anastaziya [24]
3 years ago
7

A 0.6 kg block attached to a spring of force constant 13.6 N/m oscillates with an amplitude of 9 cm. Find the maximum speed of t

he block. Answer in units of m/s. 003 (part 2 of 4) 10.0 points Find the speed of the block when it is 4.5 cm from the equilibrium position. Answer in units of m/s. 004 (part 3 of 4) 10.0 points Find its acceleration at 4.5 cm from the equilibrium position. Answer in units of m/s 2 . 005 (part 4 of 4) 10.0 points Find the time it takes the block to move from x = 0 to x = 4.5 cm. Answer in units of s.
Physics
1 answer:
mash [69]3 years ago
7 0

Answer:

1) 0.43 meters per second

2) 0.21 meters per second

3) 1.02 \frac{m}{s^{2}}

4) 0.66 seconds

Explanation:

part 1

By conservation of energy, the maximum kinetic energy (K) of the block is at equilibrium point where the potential energy is zero. So, at the equilibrium kinetic energy is equal to maximum potential energy (U):

K=U

\frac{mv^2}{2}=\frac{kx_{max}^2}{2}

With m the mass, v the speed, k the spring constant and xmax the maximum position respect equilibrium position. Solving for v

v=\sqrt{\frac{kx_{max}^2}{m}}=\sqrt{\frac{(13.6)(0.09m)^2}{0.6}}=0.43\frac{m}{s}

part 2

Again by conservation of energy we have kinetic energy equal potential energy:

\frac{mv^2}{2}=\frac{kx_{max}^2}{2}=

v=\sqrt{\frac{kx_{max}^2}{m}}=\sqrt{\frac{(13.6)(0.045m)^2}{0.6}}=0.21\frac{m}{s}

part 3

Acceleration can be find using Newton's second law:

F=ma

with F the force, m the mass and a the acceleration, but elastic force is -kx, so:

-kx=ma

a= -\frac{kx}{m}=-\frac{(13.6)(0.045)}{0.6}=-1.02\frac{m}{s^{2}}

part 4

The period of an oscillator is the time it takes going from one extreme to the other one, that is going form 4.5 cm to -4.5 cm respect the equilibrium position. That period is:

T=2\pi\sqrt{\frac{m}{k}}=T=2\pi\sqrt{\frac{0.6}{13.6}}=1.32s

So between 0 and 4.5 cm we have half a period:

t=\frac{T}{2}=0.66s

You might be interested in
2. State law of conservation of
butalik [34]

Answer:

In collisions between two isolated objects Newton's third law implies that momentum is always conserved. In collisions between two isolated objects momentum is always conserved. Kinetic energy is only conserved in elastic collisions.

Explanation:

3 0
2 years ago
Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)
levacccp [35]

Answer:

An object can have both kinetic and potential energy at the same time. ... As an object falls its potential energy decreases, while its kinetic energy increases. The decrease in potential energy is exactly equal to the increase in kinetic energy. Another important concept is work.

Explanation:

5 0
2 years ago
Read 2 more answers
What is the best description of the relationship between emerging scientific ideas and open-mindedness?
Vilka [71]
The third one looks correct to me
3 0
3 years ago
What would happen to the wavelength if the frequency was doubled?
ira [324]

Answer:

λ = hv

If frequency is doubled :

λ = h × 2v

λ = 2hv

Thus wavelength is doubled

7 0
3 years ago
A certain radio wave has a wavelength of 6.0 × 10-2m. What is its frequency in hertz?
rodikova [14]

Answer:

The frequency of the wave is 5 x 10⁹ Hz

Explanation:

Given;

wavelength of the radio wave, λ = 6.0 × 10⁻²m

radio wave is an example of electromagnetic wave, and electromagnetic waves travel with speed of light, which is equal to 3 x 10⁸ m/s².

Applying wave equation;

V = F λ

where;

V is the speed of the wave

F is the frequency of the wave

λ  is the wavelength

Make F the subject of the formula

F = V /  λ

F = (3 x 10⁸) / (6.0 × 10⁻²)

F = 5 x 10⁹ Hz

Therefore, the frequency of the wave is 5 x 10⁹ Hz

8 0
3 years ago
Other questions:
  • Which type of variable is most related to the data gathered from an experiment?​
    11·1 answer
  • A 10 kg block is pushed with a constant horizontal force of 20 n against a constant horizontal frictional force of 10 n. What is
    9·1 answer
  • spring stretches by 21.0 cm when a 135 N object is attached. What is the weight of a fish that would stretch the spring by 43.9
    6·1 answer
  • calculate the time (in years) it would take to send a message to the Galactic Capitol located at the center of our Milky Way gal
    7·1 answer
  • A force of 300 N is used to stretch a horizontal spring with a 0.5 kg block. The length of spring is 0.25 m. The block is releas
    14·1 answer
  • A 27.4 kg dog is running northward at 2.19 m/s , while a 7.19 kg cat is running eastward at 2.78 m/s . Their 75.7 kg owner has t
    10·1 answer
  • Fill in the blank.
    5·1 answer
  • 2 Points<br> Mechanical energy is the ___<br> of kinetic energy and potential energy.
    9·2 answers
  • Direction of wind: from to​
    6·1 answer
  • (5 Points)
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!