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3 years ago

3. The direction of the centripetal force acting on a ball on a string being spun in a circle around a person is

Physics

2 answers:

Yakvenalex [24]3 years ago

6 0

Answer: The correct answer is "center-seeking".

Explanation:

Centripetal force is the force which is required to keep the body in the circular motion. The direction of the centripetal force is towards center of the circle.

The expression for the centripetal force is as follows;

$F= \frac{mv^{2} }{r}$

Here, r is the radius, v is the velocity and m is the mass of the object.

Without this force, the body cannot move in the circular motion. Then, it follows the straight line motion.

The direction of the centripetal force acting on a ball on a string being spun in a circle around a person is center-seeking.

Therefore, the correct option is (D).

ruslelena [56]3 years ago

4 0

D. center seeking. Good Luck

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JulsSmile [24]

I am assuming you know the relation obtained between slit width, distance of screen from slits, distance of interference pattern obtained on the screen from the center and the wavelength of monochromatic light used in Young's Double Slit experiment.
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3 years ago

6. During an impact time casting 5 x 10-45 a gulf club exerts an average impar

Novay_Z [31]

Answer:

2.5 × 10-⁴¹ Ns

Explanation:

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3 years ago

If a planet has the same mass as the earth, but has twice the radius, how does the surface gravity, g, compare to g on the surfa

shepuryov [24]

Answer:

The surface gravity g of the planet is 1/4 of the surface gravity on earth.

Explanation:

Surface gravity is given by the following formula:

$g=G\frac{m}{r^{2}}$

So the gravity of both the earth and the planet is written in terms of their own radius, so we get:

$g_{E}=G\frac{m}{r_{E}^{2}}$

$g_{P}=G\frac{m}{r_{P}^{2}}$

The problem tells us the radius of the planet is twice that of the radius on earth, so:

$r_{P}=2r_{E}$

If we substituted that into the gravity of the planet equation we would end up with the following formula:

$g_{P}=G\frac{m}{(2r_{E})^{2}}$

Which yields:

$g_{P}=G\frac{m}{4r_{E}^{2}}$

So we can now compare the two gravities:

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When simplifying the ratio we end up with:

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3 years ago

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mojhsa [17]

Answer:

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Elena L [17]

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Normally, calorimetry is directly linked with the thermal capacity that an element has to contain heat.

See more about calorie at brainly.com/question/22374134

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