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3 years ago

3. The direction of the centripetal force acting on a ball on a string being spun in a circle around a person is

Physics

2 answers:

Yakvenalex [24]3 years ago

6 0

Answer: The correct answer is "center-seeking".

Explanation:

Centripetal force is the force which is required to keep the body in the circular motion. The direction of the centripetal force is towards center of the circle.

The expression for the centripetal force is as follows;

$F= \frac{mv^{2} }{r}$

Here, r is the radius, v is the velocity and m is the mass of the object.

Without this force, the body cannot move in the circular motion. Then, it follows the straight line motion.

The direction of the centripetal force acting on a ball on a string being spun in a circle around a person is center-seeking.

Therefore, the correct option is (D).

ruslelena [56]3 years ago

4 0

D. center seeking. Good Luck

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An eagle is flying horizontally at a speed of 3.10 m/s when the fish in her talons wiggles loose and falls into the lake 6.10 m

Alinara [238K]

Answer:

10.93m/s with the assumption that the water in the lake is still (the water has a speed of zero)

Explanation:

The velocity of the fish relative to the water when it hits the water surface is equal to the resultant velocity between the fish and the water when it hits it.

The fish drops on the water surface vertically with a vertical velocity v. Nothing was said about the velocity of the water, hence we can safely assume that the velocity if the water in the lake is zero, meaning that it is still. Therefore the relative velocity becomes equal to the velocity v with which the fish strikes the water surface.

We use the first equation of motion for a free-falling body to obtain v as follows;

v = u + gt....................(1)

where g is acceleration due to gravity taken as 9.8m/s/s

It should also be noted that the horizontal and vertical components of the motion are independent of each other, hence we take u = 0 as the fish falls vertically.

To obtain t, we use the second equation of motion as stated;

$h=ut+gt^2/2.................(2)$

Given; h = 6.10m.

since u = 0 for the vertical motion; equation (2) can be written as follows;

$h=\frac{1}{2}gt^2............(3)$

substituting;

$6.1=\frac{1}{2}*9.8*t^2\\6.1=4.9t^2\\hence\\t^2=6.1/4.9\\t^2=1.24\\t=\sqrt{1.24}=1.12s$

Putting this value of t in equation (1) we obtain the following;

v = 0 + 9.8*1.12

v = 10.93m/s

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3 years ago

Find the work done by a 75.0 kg person in climbing a 2.50 m flight of stairs at a constant speed.

Lubov Fominskaja [6]

Answer:

<em>1,839.375 Joules</em>

Explanation:

Work is said to be done is the force applied to an object cause the object to move through a distance.

Workdone = Force * Distance

Workdone = mass * acceleration due to gravity * distance

Given

Mass = 75.0kg

acceleration due to gravity = 9.81m/s²

distance = 2.50m

Substitute the given parameters into the formula:

Workdone = 75.0*9.81*2.50

Workdone = 1,839.375Joules

<em>Hence the workdone is 1,839.375 Joules</em>

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3 years ago

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Answer:

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