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Nuetrik [128]
3 years ago
9

In what two ways can we increase the potential difference?

Physics
1 answer:
vredina [299]3 years ago
4 0
Yes I hope this helps
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You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While
ANTONII [103]

To solve this problem it is necessary to apply the concepts related to the Rotational Force described from the equilibrium and Newton's second law.

When there is equilibrium, the Force generated by the tension is equivalent to the Force of the Weight. However in rotation, the Weight must be equivalent to the Centrifugal Force and the tension, in other words:

W = F_T + m\omega^2r_E

Where

\omega = \frac{2\pi}{T} \rightarrow Angular velocity is equal to the Period, at this case Earth's period

r_E = 6.371*10^6m \rightarrow Radius of the Earth

m = mass

F_T= Force of Tension

W = mg \rightarrow Newton's second law

Replacing and re-arrange to find the Tension we have,

F_T = W- \frac{W}{g} (\frac{2\pi}{T})^2r_E

F_T = W(1-(\frac{2\pi}{T})^2\frac{r_E}{g})

F_T = (505)(1-(\frac{2\pi}{24hours})^2\frac{6.371*10^6}{9.8})

F_T = (505)(1-(\frac{2\pi}{24hours(\frac{3600s}{1hour})})^2\frac{6.371*10^6}{9.8})

F_T = (505)(1-(\frac{2\pi}{86400})^2\frac{6.371*10^6}{9.8})

F_T = 503.26N

Therefore when Sneezy is on the equator he is in a circular orbit with a Force of tension of 503.26N

7 0
2 years ago
Which would be a common-sense practice in a lab environment?
algol13
Using safe research practices would be a very good common-sense practice in a lab environment.
6 0
3 years ago
A syrup added to an empty container with a mass of 115.25g . When 0.100 pint of syrup is added, the total mass of the container
sesenic [268]
<span>Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. We calculate as follows:

Density = 182.48 g - 115.25 g / 0.100 pint ( 0.47 L / 1 pint ) = 67.23 g/0.047L
Density =1430.43 g/L </span>
3 0
3 years ago
A tree is 257 ft high. To the nearest tenth of a meter, how tall is it in meters? There are 3.28 ft in 1 m.
olga2289 [7]

Answer:

Height of tree = 78.35 meters.

Explanation:

We have

          1 meter = 3.28 feet

That is

          1 ft = \frac{1}{3.28}=0.3048m

Here height of tree = 257 ft

Height of tree = 257 x 0.3048 = 78.35 m

Height of tree = 78.35 meters.

7 0
3 years ago
Write your answer to the question below.
ElenaW [278]

Answer:

Hi... Potential energy is converted to kinetic energy and kinetic energy is converted to potential energy

8 0
2 years ago
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