Answer:
Force the floor exerts on the passenger is 833 N.
Explanation:
- Weight of passenger (
) = mg = 85 × 9.8 N = 833 N
- Force the floor exerts on the passenger (
) = ?
- For the elevator with the speed as 2.0 m/s the net force is zero, it means that the force is balanced.
i.e. = - = -mg = 833 N
hence is 833 N
- If the lift was not at a constant speed i.e. if it had acceleration (
) then the case would be different.
no question please so what's the problem
Answer:
5.01 J
Explanation:
Info given:
mass (m) = 0.0780kg
height (h) = 5.36m
velocity (v) = 4.84 m/s
gravity (g) = 9.81m/s^2
1. First, solve for Kinetic energy (KE)
KE = 1/2mv^2
1/2(0.0780kg)(4.84m/s)^2 = 0.91 J
so KE = 0.91 J
2. Next, solve for Potential energy (PE)
PE = mgh
(0.0780kg)(9.81m/s^2)(5.36m) = 4.10 J
so PE = 4.10 J
3. Mechanical Energy , E = KE + PE
Plug in values for KE and PE
KE + PE = 0.91J + 4.10 J = 5.01 J
Answer:
its direction is changing
