Answer:
The value is
Explanation:
From the question we are told that
The depth of the mountain is
Generally the velocity of the surface wave is mathematically represented as
=>
=>
Generally using the Froude number is mathematically represented as
Here V is the velocity of the current
Given that the waves do not travel upstream, then the flow of the current is supercritical which means that
=>
=>
Hence the minimum velocity of the current is
This because the velocity of the current is greater velocity of the surface wave , so minimum will be like the lowest possible value of V which is v
Its a waste of time, you have to not only write it down, but study it after too . other than that notes are great.
5,758.5 miles or thr moon is a quarter of the diameter of the earth
Answer:
Final velocity of the first person is 3.43m/s and that of the second person is 0.0242m/s
Explanation:
Let the momentum of the first person, the ball second person be Ma, Mb and Mc.
From the principle of the conservation of momentum, sum of the momentum before collision is equal to the sum of the momentum after collision.
Ma1 + Mb1 = Ma2 + Mb2.
The ball and the first person are both moving together with a common velocity 3.45m/s.
Let the velocity of the first person be v1
Therefore
67.5×3.45+ 0.041×3.45= 67.5v1 + 0.041×34
233.02 = 1.39+ 67.5v1
67.5v1 = 233.02 - 1.39 = 231.61
v1 = 231.61 / 67.5
v1 = 3.43m/s
The second person and the ball move together with a common velocity after catching the ball.
For the second person and the ball let their final common velocity be v
Mb2 + Mc2 = Mb3 + Mc3
0.041 × 34 + 57.5 ×0 = (57.5 + 0.041)×v
57.541v = 1.39
v = 1.39 /57.541
v = 0.0242m/s
Answer:
The average velocity of the ball is 1.355 cm/s.
Explanation:
Given;
initial displacement of the ball, x₁ = 8.4 cm
final displacement of the ball, x₂ = 4.2 cm
initial time, t₁ = 3.0 s
final time, t₂ = 6.1 s
The average velocity of the ball is calculated as;
Therefore, the average velocity of the ball is 1.355 cm/s.