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olga2289 [7]
4 years ago
15

Suppose a planet is discovered by the Doppler technique and is then discovered to have transits. In that case, we can determine

all the following about the planet except ______________.
a) its rotation period
b) its orbital period
c) its physical size (radius)
d) its precise mass
e) its density
Physics
1 answer:
vredina [299]4 years ago
7 0

Answer:

option A

Explanation:

The correct answer is option A

Doppler technique is used in sound as well as light. Scientist uses this technique to study the universe by determining how fast stars and galaxies.

Transit is a phenomenon takes place when celestial body celestial passes directly between a larger body and the observer.

Using the Doppler effect we can determine the characteristics of the planet like the orbital period of the planet, size of the planet, mass and density of the planet.

The characteristics of the planet which we cannot find are The rotational period.

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What is inside of a blackhole ?
horsena [70]
We don't know. A black hole is a star that has collapsed into its own gravity. The gravity in fact, is so strong that even light cannot get through it. That's why it looks black to us.
7 0
3 years ago
Which of the following terms describes a process for which Q = +450 J?
Sidana [21]

Answer:

Quantity of heat or heat energy

Explanation:

the quantity of heat is the calculation of the total quantity of thermal energy in an object. it's S.I unit is joules (J) and the symbol for calculating it is Q.

4 0
3 years ago
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What is converted to sound waves by a speaker? it's on my seneca lol
marusya05 [52]

Answer:

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8 0
2 years ago
An electron enters a region of space containing a uniform 2.71 × 10 − 5 2.71×10−5 T magnetic field. Its speed is 197 197 m/s and
Andrews [41]

Answer:

r = 0.0414mm

F = 757,692.3Hertz

Explanation:

If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as

F = qvBsintheta... 1

Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as

Fc = mv²/r... 2

Equating both forces

F = Fc

qvBsin theta = mv²/r

Since the body enters perpendicular to the field, theta = 90°

The equality becomes;

qvB sin90° = mv²/r

qvB = mv²/r

qB = mv/r

r = mv/qB

Given mass of the electron m = 9.11×10^-31kg

Velocity of the object v = 197m/s

Charge on the electron q = 1.6×10^-19C

Magnetic field B = 2.71×10^-5T

Substituting this value into the equation to get the radius r we have;

r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5

r = 1794.67×19^-31/4.336×10^-24

r = 413.89×10^-7

r = 0.0000414m

r = 0.0414mm

b) Frequency of the motion F = w/2π where w is the angular velocity

Since w = v/r

F = (v/r)/2π

F = v/2πr

F = 197/2π(0.0000414)

F = 757,692.3Hertz

6 0
4 years ago
A car drives 16 miles south and then 12 miles west. what is the magnitude of the car’s displacement?
saw5 [17]

Answer:

Car's displacement is 20 miles

Explanation:

The shortest path covered by a particle is called its displacement. It is given that, a car drives 16 miles south and then 12 miles west.

From the attached figure, OA = 12 miles

OB = 16 miles

So, their resultant is equal to the displacement, i.e. AB. So,

AB=\sqrt{OA^2+OB^2}

AB=\sqrt{12^2+16^2}

AB = 20 miles

So, the car's displacement is 20 miles. Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
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