Answer:
Power output = 96.506 watts
Explanation:
Drag coefficient (Cd) = 0.9
V = 7.3 m/s
Air density (ρ) = 1.225 kg/m^(3)
Area (A) = 0.45 m^2
Let's find the drag force ;
Fd=(1/2)(Cd)(ρ)(A)(v^(2))
So Fd = (1/2)(0.9)(1.225)(0.45)(7.3^(2)) = 13.22N
Drag power = Drag Force x Drag velocity.
Thus drag power, = 13.22 x 7.3 = 96.506 watts
<h2><em>what is the correct order of the steps in the scientific </em><em>method</em></h2>
- <em>Make a hypothesis, test the hypothesis, analyze the results, ask a question, draw conclusions, communicate results.</em>
<em>hope</em><em> </em><em>it</em><em> helps</em>
<span>it's called Diastrophism</span>
Answer:
C) The speed of the freight car decreases.
Explanation:
The speed of the freight car decreases, because the sand load increases the mass of the system.
Using the conservation of linear momentum
The linear momentum m*v is an amount that must be preserved, so this equality must be satisfied before and after the sand is added to the freight car.
Subindices 1 are for before the sand is added, and subindices 2 for after the sand is added.
In this case the mass in the second moment is greater due to the mass added by the sand than the original mass , so to maintain equality the speed in this situation must decrease.
Explanation:
ω = 30 rev × (2π rad/rev) / (6 sec)
ω = 10π rad/s
ω ≈ 31.4 rad/s