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andrezito [222]
3 years ago
14

PLS HELP Do you believe this relationship between incident and reflected angles would occur even if the medium interface were cu

rved, like a curved mirror? Justify your response.
Physics
1 answer:
Anna35 [415]3 years ago
4 0
The Law of reflection would still hold even off a curved surface. Since the angles are measured from the normal, which is perpendicular to the surface, curved surfaces don't matter. This is basis of curved mirrors such as concave and convex 
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The plum pudding model of the atom states that
seropon [69]

Answer:

According to this model, the atom is a sphere of positive charge, and negatively charged electrons are embedded in it to balance the total positive charge.

Explanation:

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3 years ago
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If 3.0 newtons are required to lift a carton 12 meters, how much work is done? 0.0 J 4.0 J 15 J 36 J
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The answer is actually 36 J.

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Which one of the following SI base units is not matched to the correct unit of measurement?
ahrayia [7]
C.Lenth: Km; This answer isn´t correct.

the correct unit of measurement of length is "m".

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A student stays at her initial position for a bit of time, then walks slowly in a straight line for a while, then stops to rest
True [87]

Answer:

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

Third interval, walk back, straight downhill

Explanation:

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              x = v t

 

The first interval is walked slowly, this is a straight line with a small slope

Second interval stops, which gives a horizontal line, indicating the same position

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6 0
2 years ago
A sample of a monatomic ideal gas initially at temperature T, undergoes a process during which the pressure of the gas triples a
Allisa [31]

Answer:

B) 8 T.

Explanation:

For an ideal gas , the gas law that it follow is as follows

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In this case following information are given

P₂ / P₁ = 3

V₂ / V₁ = 3

T₁ = T

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From the gas law formula given , we have

T_2 =\frac{P_2\times V_2\times T_1}{P_1\times V_1}

V_2 = \frac{P_2}{P_1} \times\frac{V_2}{V_1}\times T

= 3 X 3 T

= 9 T

Change in temperature = 9T - T = 8 T.

7 0
2 years ago
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