2 years ago

A flexible container at an initial volume of 5.120 L contains 8.500 mol of gas.

Chemistry

1 answer:

SOVA2 [1]2 years ago

6 0

Answer:

30.05 mol

Explanation:

solving the proportion

V1 / n1 = V2 / n2

5.120 L 18.10 L

–––––––– = ––––––

8.500 mol x

x = 30.05 mol

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