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-Dominant- [34]
4 years ago
10

How would you classify raisin bran?

Chemistry
1 answer:
Nostrana [21]4 years ago
6 0
Pure substance element I think
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When air bags inflate, nitrogen gas is formed from sodium azide, along with solid sodium. what reaction category is this?
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alkaline silocate
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Naming ionic compounds what are the structural units that make up ionic compounds and how are they named answers
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3 years ago
A container was found in the home of the victim that contained 120 g of ethylene glycol in 550 g of liquid. How many drinks, eac
Andrei [34K]

Answer:

0.432 drinks are toxic

Explanation:

The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):

1.11g/mL * (0.1mL / kg) =  0.111g/kg

If the victim weighs 85kg, its letal dose is:

85kg * (0.111g/kg) = 9.435g of ethylene glycol

Using the concentration of ethylene glycol in the liquid:

9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.

The drinks are:

43.2g of liquid * (1 drink / 100 g) =

<h3>0.432 drinks are toxic</h3>
5 0
3 years ago
Identify the catalyst in this reaction, explain how
telo118 [61]

Question:

Sulfuric acid was once produced through the reaction of sulfur trioxide with water. Sulfur trioxide can form through the reaction of sulfur dioxide and oxygen gas. When nitrogen monoxide gas is added to the system, the reaction speeds up significantly because it proceeds through the following steps:

equations

Identify the catalyst in this reaction, explain how you know it is the catalyst, and describe how it increases the rate of the reaction.

Answer:

NO

It is present but not consumed

NO Lowers the activation energy of the reaction

Explanation:

A catalyst is a substance that is present in a chemical reaction and enables the reaction to occur at a faster rte but does not take part n the reaction

Therefore, whereby NO is not consumed, it is the catalyst

It functions by lowering the activation energy

5 0
3 years ago
Propane (c3h8) is burned in oxygen to produce carbon dioxide and water. the heat of combustion of propane is -2012 kj/mole. how
Olegator [25]
C_{3} H_{8} + 5 O_{2} ---\ \textgreater \  3CO_{2}  +4H_{2}O    (-2012 \frac{kJ}{mol} )&#10;&#10;&#10;3 mol                10 mol&#10;&#10;&#10;C_{3}H_{8} is /excess /reactant&#10;&#10;because 3 mol propane require 15 mol oxygen (by reaction)&#10;&#10;5 mol oxygen ---1 mol propane, so&#10;&#10;10 mol oxygen ---2 mol propane&#10;&#10;Only 2 mole propane will be burned,&#10;&#10;so &#10;&#10;2012 ( kJ/mol)*2 mol =4024 KJ heat will be given off&#10;&#10;Correct answer is number 4.&#10;&#10;&#10;
5 0
3 years ago
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