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Salsk061 [2.6K]
3 years ago
10

5 subtract negative 2

Mathematics
2 answers:
liberstina [14]3 years ago
8 0

Answer:

the answer is 7 because 2 negatives together is a positive

Goryan [66]3 years ago
7 0

Answer:

7

Step-by-step explanation:

5-(-2)

5+2

7

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4) Solve for x.<br> y = 9x – XZ
kogti [31]

Answer:

the answer is x=y/9 + XZ/9

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

4 0
3 years ago
I need help with all of these!!
kifflom [539]
7=7
8=2
9=one solution
10=b=3p
       s=b-2.50
11=b=6.75
       p=2.25
       s=4.25


5 0
4 years ago
Find the sum.<br> (X+3)+(2x-1)
leonid [27]

Answer:

3x+2

Step-by-step explanation:

x+3+2x−1

=x+3+2x+−1

Combine Like Terms:

=x+3+2x+−1

=(x+2x)+(3+−1)

=3x+2

Brainliest plz. If you want...

7 0
3 years ago
Justin weighs 72 kilograms. What is his weight in pounds?
Thepotemich [5.8K]
He is 158.733 pounds 
7 0
4 years ago
Show that 3x^2 -2x + 1 is always greater than 0.<br> ( This is an Additional Math Question )
Leviafan [203]

Answer:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

Step-by-step explanation:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)

Consider x^2-2/3x+1/3

Remember that (a-b)^2 =a^2-2ab+b^2

x^2=a^2

a=x

-2/3x= -2*x*b

b=1/3

S0 (x-1/3)^2= x^2-2/3x+1/9

x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

6 0
3 years ago
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