1) use energy from food
2) get rid of wastes
3) maintain
Differentiation in its simplest of terms means breaking something into small parts. On the other hand, integration is taking those really small parts and gluing them in the right order. In short, these terms are the direct opposite or inverses of each other. The term which can tell you how fast you are going at a moment in time at ones current location is called a derivative. The term on the other hand, which can tell you how far you have travelled if you have been keeping track of your location and your time is what an integral is referred to. It is like differentiation only needs knowledge on the local neighbourhood while integration will need the knowledge on a global knowledge.
Answer:
Length = 2.92 m
Diameter = 0.11 mm
Explanation:
We have
, where:
is the length

We divide the first equation by the second equation to get:


Using this Area, we find the diameter of the wire:



To find the length, we multiply the two equations stated initially:


Calm, sunny days with wind moving away from the center.