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3 years ago

Compare and contrast the particle motion in each state of matter

Physics

1 answer:

Vladimir79 [104]3 years ago

6 0

Answer:

Gases, liquids and solids are all made up of microscopic particles, but the behaviors of these particles differ in the three phases. ... gas are well separated with no regular arrangement. liquid are close together with no regular arrangement. solid are tightly packed, usually in a regular pattern.

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How do creepers explode

Nataliya [291]

Answer:

From you getting close to them

Explanation:

Because its big brain time.

6 0

3 years ago

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A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a=a1

AlekseyPX

Explanation:

A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression :

$a=a_1+\dfrac{F}{m}$

Where

$a_1=3\ m/s^2$

$F=12\ kg-m/s^2$

m = 7 kg

So, the correct step for obtaining a common denominator for the two fractions in the expression in solving for a is (a) and the value of a is :

$a=3+\dfrac{12}{7}$

$a=4.71\ m/s^2$

Hence, the correct option is (a).

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3 years ago

The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve o

DIA [1.3K]

The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve of the particle at the origin in cosinusoidal form is shown in the figure.

Try to find (1) the vibration function of the particle at the origin, (2) the wave function of the planar simple harmonic wave according to the origin.

7 0

3 years ago

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4. A car is accelerating at 40 m/s2, if the car is 400 kg how much force

Ksenya-84 [330]

Sorry I’m only in kindergarten is it 10kg must be supplied???

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3 years ago

New 5G networks utilize millimeter-wave radiation. Millimeter-wave radiation refers to electromagnetic waves with frequencies in

seraphim [82]

Answer:

It corresponds to 1mm-10 mm range.

Explanation:

Electromagnetic waves (such as the millimeter-wave radiation) travel at the speed of light, which is 3*10⁸ m/s in free space.
As in any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

$v = \lambda * f (1)$

Replacing v= c=3*10⁸ m/s, and the extreme values of f (which are givens), in (1) and solving for λ, we can get the free-space wavelengths that correspond to the 30-300 GHz range, as follows:

$\lambda_{low} = \frac{c}{f_{high}} = \frac{3e8m/s}{300e9Hz} = 1 mm (2)$

$\lambda_{high} = \frac{c}{f_{low}} = \frac{3e8m/s}{30e9Hz} = 10 mm (3)$

4 0

3 years ago