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labwork [276]
3 years ago
5

Explain why reactivity increases by linking increase in atomic number, number of shells with the shielding of outer most electro

n
Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0
The higher the atomic number, the more shells an atom has. the electrons in the outer shell are more reactive as they have a weaker attraction to the nucleus as they are furthest away from the nucleus.
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What is the relative rate of diffusion of hydrogen and nitrogen ​
vredina [299]

Answer:

2.645

Explanation:

Rate of diffusion formula:

Sqrt(mass2/mass1)

>>sqrt(14/2)

(Note:Hydrogen must exist in dwiatomic, [H2])

3 0
2 years ago
8.5C (H)
Zigmanuir [339]

Answer:

Boron.

Explanation:

5 0
3 years ago
Which of the following is most likely to form multiple (double or triple) bonds? 1. Li 2. Cl 3. N 4. H 5. F
alukav5142 [94]

Answer: Option (3) is the correct answer.

Explanation:

Atomic number of lithium is 3 and its electronic distribution is 2, 1. So, to attain stability it will loose an electron and hence, it forms a single bond.

Atomic number of chlorine is 17 and it has 7 valence electrons. Hence, in order to attain stability it will gain one electron and therefore, it forms a single bond only.

Atomic number of nitrogen is 7 and its electronic distribution is 2, 5. Therefore, to attain stability it needs to gain 3 more electrons. Hence, a nitrogen atom is able to form a triple bond and also it is able to form a double bond.

Hydrogen has atomic number 1 and it attains stability by gaining one electron. Therefore, a hydrogen atoms always forms a single bond.

Atomic number of fluorine is 9 and its electronic distribution is 2, 7. To complete its octet it needs to gain one electron. Hence, a fluorine atom always forms a single bond.

Thus, we can conclude that out of the given options nitrogen is most likely to form multiple (double or triple) bonds.

3 0
3 years ago
The major reaction of the unsaturated compounds is:
antiseptic1488 [7]
Its B addition

where an atom adds to the broken double bond of a hydrocarbon and saturates it 

hope that helps
3 0
3 years ago
Read 2 more answers
A certain first-order reaction (a→products) has a rate constant of 9.60×10−3 s−1 at 45 ∘c. how many minutes does it take for the
Alexxandr [17]

The integrated rate law expression for a first order reaction is

ln\frac{[A_{0}]}{[A_{t}]}=kt

where

[A0]=100

[At]=6.25

[6.25% of 100 = 6.25]

k = 9.60X10⁻³s⁻¹

Putting values

ln\frac{100}{6.25}=9.6X10^{-3}t

taking log of 100/6.25

100/6.25 = 16

ln(16) = 2.7726

Time = 2.7726 / 0.0096 = 288.81  seconds

7 0
3 years ago
Read 2 more answers
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