Answer:
Step-by-step explanation:
We want to determine a 95% confidence interval for the mean total cholesterol level of all males.
Number of sample, n = 355
Mean, u = 185 mg
Standard deviation, s = 16
For a confidence level of 95%, the corresponding z value is 1.96. This is determined from the normal distribution table.
We will apply the formula
Confidence interval
= mean +/- z ×standard deviation/√n
It becomes
185 +/- 1.96 × 16/√355
= 185 +/- 1.96 × 0.849
= 185 +/- 1.66404
The lower end of the confidence interval is 185 - 1.66404 =183.336
The upper end of the confidence interval is 185 + 1.66404 = 186.66
Therefore, with 95% confidence interval, the mean total cholesterol level of all males is between 183.336 mg and 186.66 mg
Answer:
QR = 65.4 m
Step-by-step explanation:
a. Apply Law of Cosines to find QR:
p² = q² + r² - 2qr × Cos P
p = QR = ?
q = PR = 150 m
r = PQ = 120 m
P = 25°
Plug in the values
p² = 150² + 120² - (2)(150)(120) × Cos(25°)
p² = 22,500 + 14,400 - 36,000 × 0.9063
p² = 36,900 - 32,626.8
p² = 4,273.2
p = √4,273.2
p ≈ 65.4 m (nearest tenth)
QR = 65.4 m
Answer:
30
Step-by-step explanation:
Substitute for x and y
2 x 3 x 5 = 6 x 5 = 30
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