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Makovka662 [10]
4 years ago
7

In the seventeenth century, Robert Hooke conducted many experiments with springs. In all the data he recorded, he found that the

force needed to push down on a spring or stretch it out from its usual resting point was equal to the spring’s stiffness multiplied by the distance it is pushed or pulled from its resting point. He wrote the equation F = kX, in which F is the force, k is the spring’s stiffness, and X is the distance the end of the spring moves from its usual resting point when no push or pull is applied. The equation is still used today.
Which best describes Hooke’s equation?

A) It is a law, because it explains why a force must be applied to push or pull a spring.

B) It is a law, because it states how force relates to a spring but does not explain why.

C)It is a theory, because it explains why a force must be applied to push or pull a spring.
 
D)It is a theory, because it states how force relates to a spring but does not explain why.
Physics
2 answers:
Gnoma [55]4 years ago
7 0

Answer:

B) It is a law, because it states how force relates to a spring but does not explain why.

Explanation:

As we know that Law is defined as the hypothesis which is experimentally verified. This law is converted into theory if we can prove it mathematically with a given theory.

So here we know that in spring force calculation we obtained a relation that if spring is compressed or expanded by some distance "x" then the spring force on it will be proportional to that distance.

Since there is only experimental verification is available for this hypothesis so it must be defined as law.

so here correct answer will be

B) It is a law, because it states how force relates to a spring but does not explain why.

IgorLugansk [536]4 years ago
4 0
B.
The explanation of the relationship between load and extension is not in Hooke's Law.
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In a chemical reaction,sodium sulphate and barium chloride are mixed to form barium sulphate(a precipitate)and sodium chloride.
Jlenok [28]

Answer:

i) The reactants are sodium sulphate and barium chloride

ii) The products are barium sulphate and sodium chloride.

Explanation:

In chemistry, a chemical reaction occurs when one or more chemical substances usually referred to as REACTANTS undergoes some processes and is converted to one or more different substances known as PRODUCTS.

From the question:

Na2SO4 + BaCl2 ⟶ 2NaCl + BaSO4

​The above balanced equation represents the chemical reaction between sodium sulphate and barium chloride. Both are the reactants because they where the substances that passed through a process ( this involves the breaking of bond that held them together).

The PRODUCTS are barium sulphate and sodium chloride because they are the substances that presented at the end of the chemical reaction.

5 0
3 years ago
in December which will have a longer day length a country im notheren hemisphere or southern hemisphere​
astra-53 [7]

Answer:

Southern Hemisphere

Explanation:

3 0
3 years ago
A +5.00 pC charge is located on a sheet of paper.
emmainna [20.7K]

Answer:

a)    V = - x ( σ / 2ε₀)

c)  parallel to the flat sheet of paper

Explanation:

a) For this exercise we use the relationship between the electric field and the electric potential

          V = - ∫ E . dx        (1)

for which we need the electric field of the sheet of paper, for this we use Gauss's law. Let us use as a Gaussian surface a cylinder with faces parallel to the sheet

       Ф = ∫ E . dA = q_{int} /ε₀

the electric field lines are perpendicular to the sheet, therefore they are parallel to the normal of the area, which reduces the scalar product to the algebraic product

          E A = q_{int} /ε₀

area let's use the concept of density

        σ = q_{int}/ A

       q_{int} = σ A

          E = σ /ε₀

as the leaf emits bonnet towards both sides, for only one side the field must be

          E = σ / 2ε₀

         we substitute in equation 1 and integrate

      V = - σ x / 2ε₀  

       V = - x ( σ / 2ε₀)

if the area of ​​the sheeta is 100 cm² = 10⁻² m²

      V = - x  (10⁻²/(2 8.85 10⁻¹²) = - x  ( 5.6 10⁻¹⁰)

       

      x = 1 cm     V = -1   V

      x = 2cm     V = -2   V

This value is relative to the loaded sheet if we combine our reference system the values ​​are inverted

       V ’= V (inf) - V

       x = 1 V = 5

       x = 2 V = 4

       x = 3 V = 3

   

These surfaces are perpendicular to the electric field lines, so they are parallel to the sheet.

 

In the attachment we can see a schematic representation of the equipotential surfaces

b) From the equation we can see that the equipotential surfaces are parallel to the sheet and equally spaced

c) parallel to the flat sheet of paper

8 0
4 years ago
Find the mass of the solid cylinder Dequals​{(r,theta​,z): 0less than or equalsrless than or equals2​, 0less than or equalszless
anygoal [31]

The mass of the cylinder <em>D</em> is obtained by integrating the density function over <em>D</em>:

\displaystyle\iiint_D\rho(r,\theta\,z)\,\mathrm dV

With \rho(r,\theta,z)=1+\frac z2, and

D=\left\{(r,\theta,z)\mid 0\le r\le2,0\le z\le10\right\}

the mass would be

\displaystyle\int_0^{2\pi}\int_0^2\int_0^{10}1+\frac z2\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=4\pi\int_0^{10}1+\frac z2\,\mathrm dz

4\pi\left(z+\dfrac{z^2}4\right)\bigg|_0^{10}

=4\pi\left(10+\dfrac{100}4\right)=\boxed{140\pi}

6 0
3 years ago
(BRAINLIEST)
UkoKoshka [18]

Answer:

Gravity

because it's factorised by mass of a body.

For other forces, they deal with charges of negligible mass and weights

4 0
4 years ago
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