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KiRa [710]
3 years ago
7

The _____ usually occur in nature as combined elements.

Physics
1 answer:
notsponge [240]3 years ago
6 0
The transition metals usually occur in as combine state. .
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What exercise became part of movement in the 1970
joja [24]

Answer:

Aerobic exercise became part of this movement in the 1970s.

8 0
3 years ago
What is the distance and the displacement of the race car drivers in the Indy 500?
sladkih [1.3K]
Answer here
The displacement of the cars is somewhere near 0 miles since they virtually finish where they started. Yet the successful cars have covered a distance of 500 miles
3 0
3 years ago
The perimeter of a sector of a circle is the sum of the two sides formed by the radii and the length of the included arc. A sect
snow_tiger [21]

Answer:

Length of the arc of this sector, l = 14 cm

Explanation:

It is given that, the perimeter of a sector of a circle is the sum of the two sides formed by the radii and the length of the included arc.

Perimeter of sector, P = 28 cm

Area of sector, A=49\ cm^2

According to figure,

2r + l = 28 ............(1)

Area of sector, A=\dfrac{\theta}{360}\times \pi r^2

Where, \theta is in radian and \theta=\dfrac{l}{r}

Since, 1^{\circ}=\dfrac{\pi}{180}\ radian

A=\dfrac{l}{2\pi r}\times \pi r^2

r=\dfrac{98}{l}

Put the value of r in equation (1) so,

2\times (\dfrac{98}{l})+l=28

l^2-28l+196=0

On solving above equation for l we get, l = 14 cm. So, the length of the arc of this sector is 14 cm. Hence, this is the required solution.

5 0
3 years ago
Suppose a log's mass is 5kg. After burning, the mass of the ash is 1 kg. Explain what could have happened to the other 4kg.
snow_lady [41]
Mass never just disappears. The other 4kg had to go somewhere. It could have left the scene of the fire in the form of smoke particles and hot gases.
3 0
4 years ago
An unwary football player collides with a padded goalpost while running at a velocity of 5.70 m/s and comes to a full stop after
ollegr [7]
The relationship between the initial velocity, final velociy, distance, and deceleration can be expressed in the following equation.
          
                     2(a)(0.270 m) = 0² - (5.70 m/s)²

The value of a (which is the deceleration) is 0.06 m/s². Thus, the answer is that the deceleration value is approximately 0.06 m/s².
6 0
4 years ago
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