Answer:
a) The duration, during which the block remain in contact with the spring is 0.29 s
b) The period of the simple harmonic oscillatory motion depends only on the mass and spring constant, therefore when the speed is doubled, the duration of contact remains the same as 0.29 s.
Explanation:
Mass of the block = 465 g
Surface speed = 0.35 m/s
Spring constant , k = 54 N/m
= 0.58 s
a) Since the period for the oscillatory motion is 0.58 s, then the time when the block and spring remain in contact is T/2 = 0.29 s
b) When the speed is doubled, we have
Therefore, since T is only dependent on the mass, m and the spring constant, K, then the time it takes when the speed is doubled remain as
T /2 = 0.29 s
Explanation:
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Heya!!
For calculate aceleration, lets applicate second law of Newton:
<u>Δ Being Δ</u>
F = Force = 78,3 N
m = Mass = 24,5 kg
a = Aceleration = ?
⇒ Let's replace according the formula and clear "a":
⇒ Resolving
Result:
The aceleration is <u>3,19 meters per second squared (m/s²)</u>
Good Luck!!
Work = (500N)(15m)=7500J Power= (7500J)/(20s) =375 W
Hopefully this helps
Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction—or change both. If you're not changing your speed and you're not changing your direction, then you simply cannot be accelerating—no matter how fast you're going.
