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denis23 [38]
3 years ago
14

TECHNOLOGY A Lamborghini Aventador accelerates from rest to 100 km / h in 2.9 s. The mass of the car is 1575 kg Calculate the po

wer supplied by the car's engine in HP without considering drag and friction (I HP 745.7 W)
Physics
1 answer:
DerKrebs [107]3 years ago
6 0

At 100 km/hr, the car's kinetic energy is

KE = (1/2) (mass) (speed)²

KE = (1/2) (1575 kg) ( [100 km/hr] x [1000 m/km] x [1 hr/3600 sec] )²

KE = (787.5 kg) (27.78 m/s)²

KE = 607,639 Joules

In order to deliver this energy in 2.9 seconds, the engine must supply

(607,639 J / 2.9 sec) = 209,531 watts

<em>Power = 281 HP</em>

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Answer:

201.6 N

Explanation:

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r = radius of the disk = 1.50 m

w₀ = Initial angular speed = 0 rad/s

w = final angular speed = 0.700 rev/s = (0.700) (2π) rad/s = 4.296 rad/s

t = time interval = 2 s

α = Angular acceleration

Using the equation

w = w₀ + α t

4.296 = 0 + 2α

α = 2.15 rad/s²

I = moment of inertia of merry-go-round

Moment of inertia of merry-go-round is given as  

I = (0.5) m r² = (0.5) (125) (1.50)² = 140.625 kgm²

F = constant force applied

Torque equation for the merry-go-round is given as

r F = I α

(1.50) F = (140.625) (2.15)

F = 201.6 N

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3 years ago
Suppose we consider the system of the three capacitors as a single "equivalent" capacitor. Given the charges of the three indivi
emmainna [20.7K]

Answer:

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Explanation:

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8 0
3 years ago
Imagine a particular exoplanet covered in an ocean of liquid methane. At the surface of the ocean, the acceleration of gravity i
AlladinOne [14]

Answer:

Explanation:

Atmospheric pressure = 7 x 10⁴ Pa

force on  a disk-shaped region 2.00 m in radius at the surface of the ocean due to atmosphere  = pressure x area

= 7 x 10⁴ x 3.14 x 2 x 2

= 87.92 x 10⁴ N

b )

weight, on this exoplanet, of a 10.0 m deep cylindrical column of methane with radius 2.00 m

Pressure x area

height x density x acceleration of gravity x π r²

= 10 x 415 x 6.2 x 3.14 x 2 x 2

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= 7 x 10⁴ + 10 x 415 x 6.2 ( hρg)

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3 years ago
A biconvex lens is formed by using a piece of plastic(n=1.70).
creativ13 [48]

Answer:

f =17.15\ cm

Explanation:

given,

refractive index of lens, n = 1.70

Radius of curvature of front surface. R₁ = 20 cm

Radius of curvature of the back surface, R₂ = 30 cm

focal length= ?

\dfrac{1}{f}=(n-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})

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\dfrac{1}{f}=(1.70-1)(\dfrac{1}{20}-\dfrac{1}{-30})

\dfrac{1}{f}=0.70 \times 0.0833

f = \dfrac{1}{0.7 \times 0.0833}

f =17.15\ cm

the focal length of the lens is equal to 17.15 cm

3 0
3 years ago
When the sound from two sound waves goes up and down (loud, soft, loud, soft) it makes a distinctive sound pattern called beats.
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The beats are actually two new sounds.

Their frequencies are (the sum of the original two frequencies) and (the difference of the original two frequencies).

The existence of the beats is the result of the difference in the frequencies of the original two sounds. <em> (b)</em>

8 0
3 years ago
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