Answer:
it will take for the sphere to increase in potential by 1500 V, 503.71 s.
Explanation:
The charge on the sphere after t seconds is:
q = (1.0000049 - 1.0000000) t = 0.0000049 t
The voltage on the surface is
V = k *
= k 0.0000049 t / R
solve for t
t = (R*V) / (0.0000049 k) = (0.12 * 1500) / (0.0000049 *
) = 503.71 s
Gravity is the force that attracts to bodies toward each other friction is the resistance from one thing to another
The energy needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3 will be 1.93 *10^-18J and 12.09 eV.
<h3>How to compute the value?</h3>
The following can be deduced:
Energy of electron in hydrogen atom is
En = -13.6 /n2 eV
where n is principal quantum number of orbit.
Energy of electron in first orbit = E1 = -13.6 / 12 = - 13.6eV
Energy of electron in third orbit = E3 = -13.6 /32 = -1.51 eV
Energy required to move an electron fromfirst to thirdorbit ΔE = E3- E1
ΔE = -1.51 - ( 13.6) = 12.09 eV
Energy in Joule = 12.09 *l/× 1.6 × 10^-19 = 1.93 × 10^-18 J.
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Complete question:
How much energy is needed to move an electron in a hydrogenatome from the ground state (n=1) to n=3? Give theanswer (a) in joules and (b) in eV.
I think it’s action force please tell me if I’m wrong I hope you have a wonderful day
I doubt that the physical properties will be affected, however, the chemical properties will be affected especially reaction rates