Acceleration x time = velocity
Since you're given acceleration and time, just plug the values into the equation.
3
x 1.1 s = ?
Solve that equation, and remember your velocity should be in m/s.
At t =0, the velocity of A is greater than the velocity of B.
We are told in the question that the spacecrafts fly parallel to each other and that for the both spacecrafts, the velocities are described as follows;
A: vA (t) = ť^2 – 5t + 20
B: vB (t) = t^2+ 3t + 10
Given that t = 0 in both cases;
vA (0) = 0^2 – 5(0) + 20
vA = 20 m/s
For vB
vB (0) = 0^2+ 3(0) + 10
vB = 10 m/s
We can see that at t =0, the velocity of A is greater than the velocity of B.
Learn more: brainly.com/question/24857760
Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. Spacecrafts A and B are flying parallel to each other through space and are next to each other at time t= 0. For the interval 0 <t< 6 s, spacecraft A's velocity v A and spacecraft B's velocity vB as functions of t are given by the equations va (t) = ť^2 – 5t + 20 and VB (t) = t^2+ 3t + 10, respectively, where both velocities are in units of meters per second. At t = 6 s, the spacecrafts both turn off their engines and travel at a constant speed. (a) At t = 0, is the speed of spacecraft A greater than, less than, or equal to the speed of spacecraft B?
Answer:
0.2129 mm
Explanation:
We have given volume of the paint = 1 gallon
Area that covers the paint 
We have to find the thickness of the fresh paint
So 
So the thickness of fresh paint on the wall is 0.2129 mm
Answer:
The answer is B) Isla had a different time than hazel
Explanation:
Answer:
for 4.567 I can't tell if it x 
or x 
so:
answer using x = 0.0000644697N
answer using x = 0.00644697
Explanation:
use equation F = GMm/
