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Elena-2011 [213]
3 years ago
12

What are the possible rational zeros of f(x) = x4 − 4x3 + 9x2 + 5x + 14?

Mathematics
1 answer:
Dovator [93]3 years ago
6 0

Answer:

±1, ±2, ±7, ±14

Step-by-step explanation:

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An amusement park offers two options. Option 1 involves a $10 admission fee plus $0.50 per ride. Option 2 involves a $6 admissio
Art [367]

Answer:

16 rides

Step-by-step explanation:

Option 1 . Admission fee = $10

                Each ride = $0.50

Option 2 . Admission fee = $6

                Each ride = $0.75

Let no. of rides be x

So, cost of ride according to option 1 = 0.50x

So, total cost after having x rides according to option 1 :

= 10+0.50x  ---1

Cost of ride according to option 2 = 0.75x  

So, total cost after having x rides according to option 2 :

= 6+0.75x  --2

Now to find the beak even point i.e. having the same cost

Equate 1 and 2

10+0.50x=6+ 0.75x

10-6= 0.75x-0.50x

4= 0.25x

\frac{4}{0.25} =x

16=x

Thus for 16 rides , the two options have the same cost .

Hence the break even point is 16 rides

5 0
3 years ago
Convert to factored form <br> y = x² + 6x
steposvetlana [31]

<em><u>Convert to factored form is:</u></em>

y = x(x + 6)

<em><u>Solution:</u></em>

Given that,

y = x^2 + 6x

We have to convert to factored form

Factored form means writing terms in multiplication. i.e as a product

From given,

y = x^2 + 6x

Factor out x from above given expression

y = x(x + 6)

Here, the given equation is written as product of "x" and (x + 6)

Thus the factored form is found

8 0
3 years ago
a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat
Flauer [41]
\bf \begin{cases}&#10;r=\textit{rate of the plane}\\&#10;w=\textit{rate of the wind}\\&#10;\end{cases}&#10;\\\\&#10;&#10;\begin{array}{ccccllll}&#10;&distance&rate&time(hrs)\\&#10;&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;\textit{with wind}&630&r+w&1\frac{1}{2}\\&#10;\textit{against wind}&1120&r-w&4&#10;\end{array}&#10;

\bf thus  \begin{cases}&#10;630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}&#10;\\\\&#10;1120=(r-w)4\\&#10;--------------\\&#10;630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\&#10;420=r+w\implies \boxed{420-w}=r\\&#10;--------------\\&#10;thus\\&#10;--------------\\&#10;1120=(r-w)4\implies 1120=4r-4w&#10;\\\\&#10;1120=4(\boxed{420-w})-4w&#10;\end{cases}&#10;

solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate?  well 420 - w = r  :)
5 0
2 years ago
Five more than a twice a number is less than 20. If the number is a whole number, what could the number be?
SOVA2 [1]

Answer:

C

Step-by-step explanation:

5 more than twice a number

(A number)=variable=x

2x+5<20

Subtract 5 from both sides

2x<15

Divide by 2

x<7.5

Any number below 7.5 (can't be 7.5 though)

5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B4%7D%7B3%7D%20%3D5" id="TexFormula1" title="\frac{x+4}{3} =5" alt="\frac{x+4}{3}
Paul [167]
Multiple both sides by 3
X+4=15

X=15-4

X=11

5 0
2 years ago
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