Answer:
The probability of finding a sample mean less than 18 hours is 0.0082
Step-by-step explanation:
To find the probability of finding a sample mean less than 18 hours, we need to calculate the z-score of this sample mean 18. And the probability of finding a sample mean less than 18 hours is P(z<z(18)).
Z-score can be calculated as follows:
z(18)=
where
- X is the sample mean (18 hours)
- M is the average hours dentists spend per week on fillings (20 hours)
- s is the standard deviation (10 hours)
- N is the sample size (144)
Putting the numbers, we get:
z(18)=
Using z- table we can find that P(z<z(18)) = 0.0082
I think it is 130. I hope this helps! :D
26. 5x^2+3x-2
The leading coefficient is 5.
28. -5c^2-3c+4
The leading coefficient is -5.
30. t^5+2t+11t-3
The leading coefficient is 1.
9,864,320
Hope this helps, let me know if there's anything else I can help you with :)
Answer:
\left(3+i\right)y\left(3-i\right)=10y
Step-by-step explanation:
\left(3+i\right)y\left(3-i\right)
\left(3+i\right)\left(3-i\right)y
=y\cdot \:10
=10y