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mezya [45]
3 years ago
6

Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample

Chemistry
1 answer:
Dimas [21]3 years ago
3 0

Answer:

<em>3.27·10²³ atoms of O</em>

Explanation:

To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.

The chemical formula for sodium sulfate is <em>Na₂SO₄, </em>and its molar mass is approximately 142.05\frac{g}{mol}.

We will use stoichiometry to convert from our mass of <em>Na₂SO₄ </em>to moles of <em>Na₂SO₄</em>, and then from moles of <em>Na₂SO₄ </em>to moles of <em>O </em>using the mole ratio; then finally, we will convert from moles of <em>O </em>to atoms of <em>O </em>using Avogadro's constant.

19.3g <em>Na₂SO₄</em> · \frac{1 mol Na^2SO^4}{142.05g Na^2SO^4} · \frac{4 mol O}{1 mol Na^2SO^4} ·\frac{6.022x10^2^3}{1 mol O}

After doing the math for this dimensional analysis, you should get a quantity of approximately <em>3.27·10²³ atoms of O</em>.

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4 0
3 years ago
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Which of the following groups of atoms are most likely to have similar properties?
vladimir1956 [14]
The third option because the elements mentioned in that selection are in the same group, they must have similar properties.
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What conversion factor is present in almost all stoichiometry calculations?
luda_lava [24]
<h3><u>Answer;</u></h3>

Molar mass

<h3><u>Explanation</u>;</h3>
  • Stoichiometry involves the study of quantitative relationships between the amounts of reactants used and products formed by a chemical reaction.
  • A conversion factor is a ratio of coefficients found in a balanced reaction, which can be used to inter-convert the amount of products and reactants.
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8 0
3 years ago
A gas has a pressure of 810 kPa at 227°C. What will its pressure be at 27°C?
NeX [460]

486 kPa will be the pressure of gas at 27 degrees.

Explanation:

Data given :

Initial pressure of the gas P1 = 810 kPa

initial temperature of the gas T1 = 227 degrees OR 500.15 K

final pressure of the gas =?

final temperature of the gas = 27 degrees OR 300.15 K

Gay Lussac's law is used to calculate the pressure of the gas at 27 degrees or 300.15 K

\frac{P1}{T1} = \frac{P2}{T2}

P2 = \frac{P1T2}{T1}

 Putting the values in the equation:

P2 = \frac{810 X 300.15}{500.15}

P2 = 486 KPa

486 Kpa is the pressure of the gas when temperature was reduced to 27 degrees.

5 0
3 years ago
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