Question

Methane and hydrogen sulfide form when hydrogen reacts with carbon disulfide. Identify the excess reagent and calculate how much remains after 36 L of H2reacts with 12 L of CS2.

Answer 1

Answer:

3 Litres.

Explanation:

The balance equation of reaction is written in equation (1) below;

4H2 (g) + CS2(g) -------------> CH4 (g) + 2H2S (g) ------------------------------(1).

(From the balanced equation above) one mole of methane, CH4 and two moles of Hydrogen Sulphide, H2S are being produced when one mole of carbon Sulphide, CS2 reacts with 4 moles of Hydrogen gas.

(Parameters given from the question): we have 36 litres of Hydrogen, H2 gas and 12 litres of carbon Sulphide, CS2 gas.

Therefore, 36 Litres of H2 would react completely with; 36 litres/ 4.

= 9 Litres of Carbon Sulphide.

LIMITING REAGENT: (The reagent that is totally consumed). Hydrogen gas, H2 is the limiting reactant since we have 12 litres of Carbon Sulphide, CS2.

EXCESS REAGENT: Carbon Sulphide.

Amount remaining= 12 Litres of CS2 - 9 litres that was reacted.

= 3 Litres.