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Rainbow [258]
3 years ago
10

What volume (in L) of a 2.46 M.

Chemistry
1 answer:
artcher [175]3 years ago
4 0

Answer:

0.0847L

Explanation:

The following data were obtained from the question:

C1 = 2.46 M

V1 =?

C2 = 0.758 M

V2 = 275 mL = 275/1000 = 0.275L

Using the dilution formula C1V1 = C2V2, we can confidently calculate the volume of the original solution as follows:

C1V1 = C2V2

2.46 x V1 = 0.758 x 0.275

Divide both side by 2.46

V1 = (0.758 x 0.275) /2.46

V1 = 0.0847L

Therefore, 0.0847L is needed

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Argon is a suitable choice for light bulbs because it's inert. Compared to a reactive gas like oxygen, the metal filimant would burn up in a reactive  enviroment, which is why a noble gas is used.
8 0
3 years ago
Consider this initial-rate data at a certain temperature for the reaction described by N2O3(
Yuliya22 [10]

<span><span>N2</span><span>O3</span><span>(g)</span>→NO<span>(g)</span>+<span>NO2</span><span>(g)</span></span>

<span><span>[<span>N2</span><span>O3</span>]</span> Initial Rate</span>
<span>0.1 M     r<span>(t)</span>=0.66</span> M/s
<span>0.2 M     r<span>(t)</span>=1.32</span> M/s
<span>0.3 M     r<span>(t)</span>=1.98</span> M/s

We can have the relationship:

<span>(<span><span>[<span>N2</span><span>O3</span>]/</span><span><span>[<span>N2</span><span>O3</span>]</span>0</span></span>)^m</span>=<span><span>r<span>(t)/</span></span><span><span>r0</span><span>(t)
However,
</span></span></span>([N2O3]/[N2O3]0) = 2

Also, we assume m=1 which is the order of the reaction.

Thus, the relationship is simplified to,

r(t)/r0(t) = 2

r<span>(t)</span>=k<span>[<span>N2</span><span>O3</span>]</span>

0.66 <span>M/s=k×0.1 M</span>

<span>k=6.6</span> <span>s<span>−<span>1</span></span></span>

6 0
3 years ago
Read 2 more answers
What discovery was made about particles with an accelerator in 1998
kramer

Answer/Explanation:

In June 1998 in Japan a scientist discovered that neutrinos (which is a type of particle) has weight, mass. This was later proven with some very convincing strong evidence.

<u><em>~ LadyBrain</em></u>

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3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST
snow_tiger [21]

Answer:

I think it's B

Explanation:

I might be wrong, but please tell me.

5 0
2 years ago
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq
Inga [223]

Answer:

M_{acid}=0.0444M

Explanation:

Hello,

In this case, for the given reaction:

H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

2*n_{acid}=n_{base}

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M

Best regards.

5 0
3 years ago
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