Answer:
Sm (Samarium) = [Xe] 4f6 6s2
Explanation:
Noble gas electron configuration of Sm (Samarium) = [Xe] 4f⁶ 6s²
Noble gas electron configuration of Os (Osmium) = [Xe] 4f¹⁴5d⁶6s²
Noble gas electron configuration of Ba (Barium) = [Xe] 6s²
Noble gas electron configuration of Bi (Bismuth) = [Xe] 4f¹⁴5d¹⁰6s²6p³
A completely filled s, p, d, and f orbitals have 2, 6, 10 and 14 electrons respectively. Half filled s, p, d, and f orbitals have 1, 3, 5 and 7 electrons respectively. Bi and Os have completely filled f orbitals. Sm has partially filled f orbital.
