8/5lit.. of 12M NaOH
2/5lit.. of 2M NaOH
D = m / V
d = 5.0 / 45.0
d = 0.111 g/cm³
Answer:
b.open flame because it is fundamental end of the alcohol mixes in with the flame then it will become a bigger fire
<h3>
Answer:</h3>
#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂
#2. Type of reaction: Synthesis reaction
<h3>
Explanation:</h3>
- Balanced equations are equations that obey the law of conservation of mass.
- When an equation is balanced the number of atoms of each element is equal on both side of the equation.
- Equations are balanced by putting appropriate coefficients on the reactants and products.
- In our case, we are going to put coefficients 2, 1 and 1.
- Thus, the balanced equation will be;
2C₅H₅ + Fe → Fe(C₅H₅)₂
- This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.
Answer:
a) 2.01 g
Explanation:
- Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃
First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:
- 0.0302 mol AgNO₃ *
= 0.0151 mol Na₂CO₃
So the remaining Na₂CO₃ moles are:
- 0.0340 - 0.0151 = 0.0189 moles Na₂CO₃
Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:
- 0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃
The closest answer is option a).
