Newton’s Second Law: Force = mass times acceleration.
F = 0.145 * 130
You would multiply to find the force required, not divide. Hope this helps!
Answer:
sec
Explanation:
Consider the down direction as negative and upward direction as positive.
= mass of the bullet = 0.00728 kg
= mass of the wooden block = 2.75 kg
= velocity of the bullet before striking the block = 641 ms⁻¹
= velocity of the wooden block before collision
= velocity of the wooden block + bullet after collision = V
Using conservation of momentum
ms⁻¹
Consider the motion of the wooden block in free fall after being dropped:
= Initial velocity of the wooden block = 0 ms⁻¹
= acceleration of the wooden block = - 9.8 ms⁻²
= time of travel
= Final velocity of the wooden block = - 0.85 ms⁻¹
One the basis of above set of data , we can use the kinematics equation
sec
Answer:
No
Explanation:
The supplied information about the object and train is incomplete. Acceleration is the rate at which the velocity of a body changes with time. Here the velocity and time is not given
<span>Cobalt-60 is undergoing a radioactivity decay.
The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span> n </span>⇒ remaining mass of cobalt after 3 years
T ⇒ decaying period
t ⇒ half-life of cobalt.
So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
3/t= 0.567
t = 3÷0.567
= 5.290626524
the half-life of Cobalt-60 is 5.29 years.
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Answer:
y maximum 3.54 m, value X 2.35 m
Explanation:
We have a projectile launch problem, let's calculate the maximum height of the projectile, where the vertical speed must be zero
Vyf² = Vyo² - 2g (Y-Yo)
Where Yo is the initial height of the ramp 1.5 m
0 = Vyo² -2g (Y-Yo)
Y-Yo = Voy² / 2g
Y = Yo + Voy² / 2g
Let's calculate the velocity components using trigonometry
Voy = vo without T
Vox = Vo cost
Voy = 7.3 sin 60
Vox = 7.3 cos 60
Voy = 6.32 m / s
Vox = 3.65 m / s
Let's calculate the maximum height
Y = 1.5 +6.32²/2 9.8
Y = 3.54 m
This is the maximum height from the ground
b) They ask us for the position of this point horizontally, we can calculate it looking for the time it took for the skateboarder to reach the highest point
Vfy = Voy - gt
0 = Voy - gt
t = Voy / g
t = 6.32 / 9.8
t = 0.645 s
Since there is no acceleration on the x-axis, we have a uniform movement, we can calculate the distance for this time
X = Vox t
X = 3.65 0.645
X= 2.35 m