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Inga [223]
3 years ago
10

Hi, I have a question if I calculate the average force that must be exerted on a 0.145 kg baseball for me to give it an accelera

tion of 130 m/s2. How would I get I get the acceleration would I divide 130 by 0.145 kg to get the acceleration?
​
Physics
1 answer:
faltersainse [42]3 years ago
7 0
Newton’s Second Law: Force = mass times acceleration.

F = 0.145 * 130

You would multiply to find the force required, not divide. Hope this helps!
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Why are the poles and slightly lower latitudes so cold in the summertime when they receive almost 24 hours of daylight? I know t
castortr0y [4]

Explanation:

As the earth travels around the sun in the elliptical orbit it must also be know that the axis of the earth is tilted as well.

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Look at the illustration , what concepts of heat are being shown in this pictures <br>​
Phoenix [80]
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Answer:

♥ Convection.

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3 0
3 years ago
4. The Earth is the only planet that contains storms. Tor F 5. Lightning is a form of energy made up of protons that move from c
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Answer:

4. F

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6 0
3 years ago
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in c
ohaa [14]

Answer:

 a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

          I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

        F t = 2 (m v)

therefore the average force is

         F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

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final point. Upon reaching the ground, just before the deformation begins

        Em_f = K = ½ m v²

energy is conserved in this system

        Em₀ = Em_f

        m g h = ½ m v²

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This is the velocity of the body when it reaches the ground, so the force remains

        F = 2m √(2gh)   /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

          F = m a

          a = F / m

 

          a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

         a = 2 √ (2 9.8 1.5) / 10⁻³

         a = 1.1 10⁵ m / s²

6 0
3 years ago
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