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andrezito [222]
3 years ago
14

A closed, adjustable cylinder containing 6.2 moles of oxygen gas has a volume of 4.3 liters and a pressure of 3.8 atmospheres. I

f the cylinder's volume is changed so that it is 15.5 liters, what is the new pressure of the gas? Round your answer to the nearest 0.01 atm.
Chemistry
1 answer:
il63 [147K]3 years ago
5 0

Answer:

The new pressure is 1.05 atm

Explanation:

Step 1: Data given

Number of moles oxygen gas = 6.2 moles

Volume of the cylinder = 4.3 L

Pressure of the gas = 3.8 atm

The volume changed to 15.5 L

Step 2: Calculate the new pressure

P1*V1 = P2*V2

⇒with P1 = the initial pressure of the gas = 3.8 atm

⇒with V1 = the initial volume = 4.3 L

⇒with V2 = the increased volume = 15.5 L

⇒with P2 = the new pressure = TO BE DETERMINED

3.8 atm * 4.3 L = 15.5 L * P2

P2 = (3.8 atm *4.3 L) / 15.5 L

P2 = 1.05 atm

The new pressure is 1.05 atm

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