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d1i1m1o1n [39]
3 years ago
7

A man tries to predict the winner of each of twenty football games. Excluding ties, how many different predictions are possible?

Mathematics
2 answers:
kirill [66]3 years ago
7 0

Answer:

c is the answer

Step-by-step explanation:

ch4aika [34]3 years ago
4 0

Answer:

C) 2(20)

Step-by-step explanation:

In a football game there are 2 teams playing against each other so there are 2 possible winners in a game as either of the 2 teams can win the game. So there are 2 ways to make prediction of winner for a game.

Since, there are 20 football games in total, and predictions of winner per each game are 2, so the possible predictions for 20 games would be 2 x 20

Hence, 2(20)=40 different predictions would be possible for 20 football games.

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Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.
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Answer:

When y=32, x=16.5

Step-by-step explanation:

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

We are given:

x varies inversely with y

We can write it as: x\:\alpha \:\frac{1}{y}

x=\frac{k}{y}

We have x = 132, when y=4

We can find value of k by using these values

x=\frac{k}{y}\\132=\frac{k}{4}\\k=132*4\\k=528

We need to find x when y=32

x=\frac{k}{y}\\x=\frac{528}{32}\\x=16.5

So, when y=32, x=16.5

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