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forsale [732]
3 years ago
7

Helpppppppppppppppppppp

Mathematics
1 answer:
lora16 [44]3 years ago
3 0

Answer: I think it's C


Step-by-step explanation:

(83-64)-(64+29)

83-64=19

64+29=93      

<u><em>19x-93</em></u>

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Study quadrilateral ABCD. Which graph of ABCD shows the reflection of quadrilateral ABCD across the line y=x
algol13

Answer:

graph C

Step-by-step explanation:

3 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
Which function has zeros at x = −2 and x = 5?
Sav [38]

Answer:

D:f(x) = x2 - 3x -10

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Four times the difference of b and six is equal to b squared
Tcecarenko [31]

Answer:

4(b-6)=b^2

Step-by-step explanation:

The difference would mean that it is subtraction and you multiply that difference by 4 and set it equal to b squared

3 0
3 years ago
I need this one answered too, I'm not very good at fractions...
gizmo_the_mogwai [7]

b is correct! good job :)

4 0
3 years ago
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