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Nadusha1986 [10]
2 years ago
13

What number is 15% of 325?

Mathematics
1 answer:
Rudiy272 years ago
6 0

Answer:

48.75

Step-by-step explanation:

1.

325 \times .15

2.

= 48.75

or

48 3/4

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Solve for x if the angles are 110 and 2x+3
katen-ka-za [31]

Answer:

x=16

Step-by-step explanation:

Because this is an isosceles triangle the angle 2x+3 is the same as the missing angle. The angles in triangles add up to 180 degrees. 180-110=70.

Because the two angles are the same you can divide 70 by 2 to get 35.

35=2x+3.

35-3=2x+3-3

32=2x

32/2=2x/2

16=x

7 0
3 years ago
Read 2 more answers
If fixed cost of 20 article is 500 and variable cost for each article is 40. Find the total cost function? Also ,find the total
Deffense [45]

Answer:

Cost function = 40a + 500

Cost of 90 articles = $4,100

Step-by-step explanation:

The fixed cost is $500 and it will.not change regardless of production level.

The Variable cost is $40 and increases by every additional unit produced.

Assume the number of articles produced is a.

Cost function would be:

Total cost = Variable cost * Number of articles + Fixed cost

TC = 40a + 500

Using this, the cost of 90 articles is:

= 40 * 90 + 500

= $4,100

6 0
3 years ago
Suppose f(x) = x2 and g(x) = (3x)2. Which statement best compares the graph
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  f(x) = x^2 and g(x) = (3x)^2.

g(x) can be rewritten as 9x^2.

The graph of g(x) is only one ninth as wide as that of f(x).

Next time please share the possible answer choices.  Thank you.

6 0
3 years ago
What is the solution to the equation? 2 x squared plus 4 equals 20 Choose all answers that are correct.
Stolb23 [73]
2x^2+4=20\ \ \ \ |subtract\ 4\ from\ both\ sides\\\\2x^2=16\ \ \ \ \ |divide\ both\ sides\ by\ 2\\\\x^2=8\iff x=\pm\sqrt8\\----------------------------\\\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\cdot\sqrt2=2\sqrt2\ \ \ |use\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\-----------------------------\\therefore\ your\ answer\ is\ -2\sqrt2\ and\ 2\sqrt2\to\boxed{a\ and\ c}
8 0
2 years ago
Find the value of the variable if P is between J &amp; K. <br><br> JP = 2x ; PK = 7x ; JK = 27
Nana76 [90]
J ---- P --- K

JP = 2x
PK = 7x
JK = 27

2x + 7x = 27
9x = 27
x = 27/9
x = 3

The value of P is 3.

JP = 2x = 2(3) = 6
PK = 7x = 7(3) = 21

7 0
2 years ago
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