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LenaWriter [7]
3 years ago
15

According to Lenz's law, an induced current in the direction depicted in the picture would be created when: a. An external downw

ard field is created or an external upward field is removed b. An external upward filed is created or an external upward field is removed c. An external downward field is created or an external downward field is removed d. An external upward field is created or an external downward field is removed
Physics
1 answer:
LenKa [72]3 years ago
7 0

Answer:

C. An external downward field is created or an external downward field is removed

Explanation:

As we can see that from the attached figure that the induced current would be counter clockwise. So the field occur because of induced current i.e. out of page. This represent that the current is induced in order to rise the flux out of the direction of the page

Therefore because of the external field, the field out of page & flux would be reducing or the external upward field is eliminated

So option C is correct

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Harman [31]
(a) The electron kinetic energy is
K=3.00 eV
which can be converted into Joule by keeping in mind that
1 eV=1.6 \cdot 10^{-19}eV
So that we find
K=3.00 eV \cdot 1.6 \cdot 10^{-19} eV/J =4.8 \cdot 10^{-19}J

The kinetic energy of the electron is related to its momentum p by:
K= \frac{p^2}{2m}
where m is the electron mass. Re-arranging the equation, we find
p= \sqrt{ 2Km}= \sqrt{ 2  ( 4.8 \cdot 10^{-19} J)(9.1 \cdot 10^{-31} kg) } =9.35 \cdot 10^{-25} kgm/s

And now we can use De Broglie's relationship to find its wavelength:
\lambda= \frac{h}{p}= \frac{6.6 \cdot 10^{-34} Js}{9.35 \cdot 10^{-25} kg m/s} =7.06 \cdot 10^{-10}m
where h is the Planck constant.


(b) By using the same procedure of part (a), we can convert the photon energy into Joules:
E=3.00 eV \cdot 1.6 \cdot 10^{-19} eV/J =4.8 \cdot 10^{-19}J

The energy of a photon is related to its frequency f by:
E=hf
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f= \frac{E}{h}= \frac{4.8 \cdot 10^{-19} J}{6.6 \cdot 10^{-34}Js} =7.27 \cdot 10^{14}Hz

And now we can use the relationship between frequency f, speed of light c and wavelength \lambda of a photon, to find its wavelength:
\lambda= \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{7.27 \cdot 10^{14} Hz} =4.13 \cdot 10^{-7} m
8 0
4 years ago
Find the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x2, y =
Simora [160]

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Basic Rule(1) ∫ x^n dx =x^ n+1/ n+1

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V = 128/3 * π.

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2 years ago
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Explanation:

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natta225 [31]
You might want to go to this website,       http://www.indiana.edu/~p1013447/dictionary/mendel.htm
Welcome, And i hope this helps :P
8 0
3 years ago
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