Question

A 0.10- kg ball is thrown straight up into the air with

Answer 1

Answer:(a)0,(b)1.061 kg-m/s

Explanation:

Given

mass of ball is 0.10 kg

Initial speed is 15 m/s

Maximum height reached by ball is h

$v^2-u^2=2as$

final velocity =0

$-\left ( 15\right )^2=-2\times 9.81\times s$

$s=\frac{15^2}{2\times 9.81}=11.467 m$

thus momentum of ball at maximum height is 0 as velocity is zero

For halfway to maximum height

$v^2-u^2=2as_0$

where $s_0=\frac{11.467}{2}$

$s_0=5.73 m$

$v^2=15^2-2\times 9.81\times 5.73$

v=10.61 m/s

Thus its momentum is

$mv=0.10\times 10.61=1.061 kg-m/s$