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miss Akunina [59]
3 years ago
9

A 0.10- kg ball is thrown straight up into the air with

Physics
1 answer:
mezya [45]3 years ago
3 0

Answer:(a)0,(b)1.061 kg-m/s

Explanation:

Given

mass of ball is 0.10 kg

Initial speed is 15 m/s

Maximum height reached by ball is h

v^2-u^2=2as

final velocity =0

-\left ( 15\right )^2=-2\times 9.81\times s

s=\frac{15^2}{2\times 9.81}=11.467 m

thus momentum of ball at maximum height is 0 as velocity is zero

For halfway to maximum height

v^2-u^2=2as_0

where s_0=\frac{11.467}{2}

s_0=5.73 m

v^2=15^2-2\times 9.81\times 5.73

v=10.61 m/s

Thus its momentum is

mv=0.10\times 10.61=1.061 kg-m/s

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