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Katen [24]
3 years ago
5

The brainstem is to breathing and arousal as the limbic system is to memories and: (2 points)

Physics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

The brainstem is to breathing and arousal as the limbic system is to memories and emotion. See the explanation below, please.

Explanation:

The limbic system develops certain responses to emotional stimuli (joy, anger, sadness, fear, pleasure). It interacts with the autonomic endocrine and nervous system. It is also related to sexuality, memory, attention, memories. It includes some areas such as hypothalamus, tonsil, hippocampus, among others.

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A truck moving at 45 m/s passes a police car moving at 36 m/s in the opposite direction. if the frequency of the siren is 500 Hz
elena-14-01-66 [18.8K]

Answer: observed frequency (f') = 511.97Hz

Explanation: when there is a relative motion between an observer and a sound source, the frequency of sound wave perceived by the observer is different from the frequency of originally sent out by the sound source.

This is called Doppler effect and given mathematically below as

f' = (v + v') /(v- vs) * f

f' = observed frequency

v = speed of sound in air = 340m/s

v' = velocity of observer= 45m/s

vs = velocity of source relative to observer = - 36m/s ( the negative sign came as a result of the fact that the velocity of the source is in opposite direction to the velocity of the observer)

f = original frequency of sound source = 500Hz

f' = (340 + 45)/{340 -(-36)} * 500

f' = 385/ (340 + 36) * 500

f' = 385/ 376 * 500

f' = 1.0239 * 500

f' = 511.97Hz

7 0
3 years ago
An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When the engineer first
GarryVolchara [31]

Answer:

The right answer is "1.369 m/s²".

Explanation:

The given values are:

Distance (s)

= 260 m

Initial speed (u)

= 26 m/s

Reaction time (t')

= 0.51 s

During reaction time, the distance travelled by locomotive will be:

⇒  s'=ut'

        =26\times 0.51

        =13.26 \ m

Remained distance between locomotive and car:

⇒  x=s-s'

         =260-13.26

         =246.74 \ m

Now,

The final velocity to avoid collection is, V = 0 m/s

From third equation of motion:

⇒  V^2=u^2+2ax

On putting the estimated values, we get

⇒  0=(26)^2+2\times a\times 246.74

⇒  0=676+493.48a

⇒  493.48a=-676

⇒            a=-\frac{676}{493.48}

⇒            a=1.369 \ m/s^2

3 0
3 years ago
What are tadpoles? How does it look like
AnnZ [28]

Answer: a tadpole is the first or second step into the evolution for a frog

Explanation: a frog starts with the egg then it becomes a tadpole for 6 to 12 weeks before it can start going out the water.

6 0
3 years ago
Read 2 more answers
While riding in a moving car, you toss an egg directly upward. Does the egg tend to land behind you, in front of you, or back in
bazaltina [42]

Answer:

Explanation:

The movement of a body can be analyzed using New's first law. In an inertial frame (without acceleration) every body is kept at rest or moving at constant speed until there is an external force that changes this state

Let's analyze these cases in the framework of this first law

a) If the vehicle is going at constant speed the two bodies (the egg and the hands) do not change movement so he had returned to the hands

b) If the vehicle accelerates the passenger goes faster, but the egg that is not subject to anything does not change the movement, so it falls behind the passenger

c) If the vehicle slows down, the passenger reduces its speed and the distance traveled in time, but the egg that is not attached follows its movement and falls in front of the passenger.

4 0
3 years ago
What is the distance between a 900 kg compact car and a 1600 kg pickup truck if the gravitational force between them is about 0.
elena-14-01-66 [18.8K]

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

r= \sqrt{\frac{Gm1m2}{F} }

r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m

Answer:

The distance is 0.96m

Explanation:

Given

m1= 900kg

m2= 1600kg

Force F= 0.0001nN

G=6.67430*10^-11 Nm^2/kg^2

Required:

The distance r

Step two:

the formula for the force is given as

F = Gm1m2/r2

make r subject of the formula

r= \sqrt{\frac{Gm1m2}{F} }

r= \sqrt{\frac{6.67430*10^-11*900*1600}{0.0001} }\\\\r= 0.00009610992/0.0001`}\\\\r= 0.96m

3 0
3 years ago
Read 2 more answers
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