Question

35. Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is ln y = 1.7 + .45x. What is the predicted value of y when x = .72?

Answer 1

Answer:

$y=7.57$

Step-by-step explanation:

Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is $ln y = 1.7 + .45x$

we need to predict the value of y when x=0.72

plug in the value of x in the given equation

$ln y = 1.7 + .45x$

$ln y = 1.7 + .45(0.72)$

$ln y = 1.7 + 0.324$

$ln y = 2.024$

$y=e^{2.024}$

$y=7.57$