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Dmitriy789 [7]
3 years ago
11

Suppose the car now accelerates from 0 m/s to 30.0 m/s in 5.00 s. If the wheels have a radius of 24.1 cm, what is their angular

acceleration? 6.00 rad/s-2 O 125 rad/s2 0.25 rad/s2 O 25.0 rad/s
Physics
1 answer:
Anettt [7]3 years ago
6 0

The answer is 25 and 50.3

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a person hears an echo from the top of a tower , 2.2 second after the sound is produced.how far away is the tower from the perso
bekas [8.4K]

Answer:

730.4 m

Explanation:

The sound waves travels with a uniform motion (=constant velocity), therefore we can calculate the distance it travels using the formula:

d=vt

where

d is the distance

v is the speed of the sound wave

t is the time taken

In this problem we have:

v = 332 m/s is the speed of sound in air

t = 2.2 s is the time elapsed

Therefore, the distance between the tower and the person is

d=(332)(2.2)=730.4 m

5 0
3 years ago
While getting buff at the gym you lift a bunch of weights applying 1000N of force to lift them from the ground to a height of 2m
slega [8]
A. 2000 J............
8 0
3 years ago
Please help me with this question
valkas [14]

Answer: m∠P ≈ 46,42°

because using the law of sines in ΔPQR

=> sin 75°/ 4 = sin P/3

so ur friend is wrong due to confusion between edges

+) we have: sin 75°/4 = sin P/3

=> sin P = sin 75°/4 . 3 = (3√6 + 3√2)/16

=> m∠P ≈ 46,42°

Explanation:

4 0
3 years ago
A 163 ‑turn circular coil of radius 2.65 cm and negligible resistance is immersed in a uniform magnetic field that is perpendicu
stiks02 [169]

Answer:

Explanation:

change in flux = no of turns x area of coil x change in magnetic field

= 163 x π 2.65² x 10⁻⁴ x ( .481 - 0 )

= 1728.84 x10⁻⁴  weber

rate of change of flux = change in flux / time

= 1728.84 x10⁻⁴ / .149

= 11603 x10⁻⁴ V .

volt induced = 1.16 V

current in the circuit

= volt induced / resistance

1.16 / 10.7 = .1084 A

energy dissipated = i²Rt where i is current , R is resistance and t is time.

= .1084² x 10.7 x .149

= .018734 J

= 18.73 mJ .

8 0
3 years ago
Solar winds have an influence all the way to about 160 AU from the Sun. About how many kilometers is that? 24,000,000,000 km 48,
Likurg_2 [28]

The correct answer is 24,000,000,000 km.

One AU(Astronomical Unit) is equal to 1.496 ×10⁸ kilometers.

∴ 160 AU = 160 × 1.496 ×10⁸ km

= 240 ×10⁸ Km = 24,000,000,000 km

6 0
3 years ago
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