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White raven [17]

3 years ago

9

Ugygyguygugugyub bbhjhghjgyg (bhjbgj yu

1 answer:

Elis [28]3 years ago

6 0

Answer:

what lol

Explanation:

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The speed of light is greater in a vacuum than in air or water.<br><br> True or false

Dima020 [189]

True !! Hope I helped you out a bit!

7 0

3 years ago

Read 2 more answers

____ are solid while lines stretching across one or more lanes in the same direction, indicating the proper place to come to a s

Natalka [10]

Stop lines are solid white lines painted across the traffic lanes at intersections and pedestrian crosswalks, indicating the exact place to stop.

8 0

3 years ago

We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top

frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

$F_D = c_D A \frac{\rho V^2}{2}$

Where,

F_D = Drag Force

$c_D$ = Drag coefficient

A = Area

$\rho$ = Density

V = Velocity

Our values are given by,

$c_D = 0.5$ (That is proper of a cone-shape)

$A = 9m^2$

$\rho = 1.2Kg/m^3$

$V = 6.5m/s$

Part A ) Replacing our values,

$F_D = 0.5*9*\frac{1.2*6.5^2}{2}$

$F_D = 114.075N$

Part B ) To find the torque we apply the equation as follow,

$\tau = F*d$

$\tau = (114.075N)(7)$

$\tau = 798.525N.m$

3 0

3 years ago

Calculated the measurement uncertainty for Kinetic Energy when :mass = 1.3[kg] +/- 0.4[kg]velocity= 5.2 [m/s] +/- 0.2 [m/s]KE= 1

andriy [413]

Answer:

$\rm KE\pm \Delta KE = 17.6\pm 6.8\ J.$

Explanation:

<u>Given:</u>

Mass, $\rm m\pm\Delta m = 1.3\pm 0.4\ kg.$

Velocity, $\rm v\pm \Delta v = 5.2\pm 0.2\ m/s.$

where,

$\rm \Delta m,\ \Delta v$ are the uncertainties in mass and velocity respectively.

The kinetic energy is given by

$\rm KE = \dfrac 12 mv^2 = \dfrac 12 \times 1.3\times 5.2^2=17.576\approx 17.6\ J.$

The uncertainty in kinetic energy is given as:

$\rm \dfrac{\Delta KE}{KE}=\dfrac{\Delta m}{m}+\dfrac{2\Delta v}{v}\\\dfrac{\Delta KE}{17.6}=\dfrac{0.4}{1.3}+\dfrac{2\times 0.2}{5.2}\\\dfrac{\Delta KE}{17.6}=0.384\\\Rightarrow \Delta KE = 17.6\times 0.384 = 6.7854\ J\approx6.8\ J\\\\Thus,\\\\KE\pm \Delta KE = 17.6\pm 6.8\ J.$

7 0

4 years ago

The power in an electric circuit varies inversely with the resistance. If the power is 2,200 watts when the resistance is 25 ohm

valentinak56 [21]

Answer:

The value of resistance when power is 1100 watts = $R_{2}$ = 50 ohms

Explanation:

Power $P_{1}$ = 2200 Watts

Resistance $R_{1}$ = 25 ohms

Power $P_{2}$ = 1100 Watts

Resistance $R_{2}$ = we have to calculate

Given that the power in an electric circuit varies inversely with the resistance

⇒ P ∝ $\frac{1}{R}$

⇒ $\frac{P_{2} }{P_{1} }$ = $\frac{R_{1} }{R_{2} }$

⇒ $\frac{1100}{2200}$ = $\frac{25}{R_{2} }$

⇒ $R_{2}$ = 50 ohms

This is the value of resistance when power is 1100 watts.

6 0

4 years ago