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White raven [17]
3 years ago
9

Ugygyguygugugyub bbhjhghjgyg (bhjbgj yu

Physics
1 answer:
Elis [28]3 years ago
6 0

Answer:

what lol

Explanation:

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Please help
ivanzaharov [21]

Answer:

1 +2=3 so thats it

Explanation:

Because i need points

4 0
3 years ago
Define fundamental unit ? write its two example. ​
stealth61 [152]

the International System of Units, the fundamental units are: The meter (symbol: m), used to measure length. The kilogram (symbol: kg), used to measure mass. The second (symbol: s), used to measure time. The ampere (symbol: A), used to measure electric current.

8 0
3 years ago
All of the following show friction as a useful force, except _____.
prohojiy [21]

Answer: having to push a rough and heavy box across the floor to move it

Explanation:

The Friction force is any force that is in opposite direction of the motion of an object or fluid due to the contact of this object or fluid with other bodies.

In this sense, there are different types of friction force thath are useful in different situations:

-The <u>Static friction force</u> prevents surfaces from slipping across each other. For example, the friction between your feet and the floor keeping you from slipping.

-The <u>kinetic friction force</u> as the force that helps the tires in a moving vehicle to slow down and stop when necessary.

However, if you want to push a heavy box across the floor to move it, the friction force will not be useful at all.

6 0
3 years ago
Read 2 more answers
One hundred turns of insulated copper wire are wrapped into a circular coil of crosssectional area 1.20⇥103 m2. The two ends of
arsen [322]

Answer:

236.3  x 10^-^3 C

Explanation:

Given:

B(0)=1.60T and B(t)=-1.60T

No. of turns 'N' =100

cross-sectional area 'A'= 1.2 x 10^-^3m²

Resistance 'R'= 1.3Ω

According to Faraday's law, the induced emf is given by,

ℰ=-NdΦ/dt

The current given by resistance and induced emf as

I = ℰ/R

I= -NdΦ/dtR

By converting the current to differential form(the time derivative of charge), we get

\frac{dq}{dt}=  -NdΦ/dtR

dq= -N dΦ/R

The change in the flux dФ =Ф(t)-Ф(0)

therefore, dq = \frac{N}{R} (Ф(0)-Ф(t))

Also, flux is equal to the magnetic field multiplied with the area of the coil

dq = NA(B(0)-B(t))/R

dq= (100)(1.2 x 10^-^3)(1.6+1.6)/1.3

dq= 236.3  x 10^-^3 C

5 0
4 years ago
6. A woman weighs 650 N and wears high heels with a
Anna [14]

Answer:

12.5

Explanation:

Pressure: Force/Area = 650/52

=12.5

6 0
3 years ago
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