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nika2105 [10]
3 years ago
8

I need to choose a theme for my physics assignment My experiment is finding g

Physics
1 answer:
Kobotan [32]3 years ago
5 0
<h3>Question:</h3>

How to find g (acceleration due to gravity)

<h3>Solution:</h3>

We know,

Acceleration due to gravity (g)

=  \frac{GM}{ {R}^{2} }

where, G = Gravitational constant

= 6.67 \times  {10}^{11} N {m}^{2}/k {g}^{2}  \\

M = Mass of the earth

= 6 \times  {10}^{24} \:  kg

R = Radius of the earth

= 6.4 \times  {10}^{6} m

Putting these values of G, M and R in the above formula, we get

g \:  =  \:  \frac{6.67 \times  {10}^{11} N {m}^{2}/k {g}^{2}   \times \: 6 \times  {10}^{24} \:  kg }{(6.4 \times  {10}^{6}m {)}^{2}  }  \\  = 9.8m/ {s}^{2}

So, the value of acceleration due to gravity is

9.8m/s ^{2}

Hope it helps.

Do comment if you have any query.

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F_{23} = G \frac{m_{3}.m_{2}}{(r_{23})^2}............................(2)

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F_{21} = 2.2233\times 10^{-11} N

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F_{23} = 6.67 \times 10^{-11 }\times \frac{1\times 4}{3^2}

F_{23} = 2.9644\times 10^{-11} N

∵Mass m_{2} is in the middle of the masses m_{3} & m_{1} therefore the forces  F_{23} & F_{21} will attract them in radially opposite direction.

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