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Allushta [10]
4 years ago
7

PLS HELP!!!! If u help I will mark brainiest thx

Physics
1 answer:
tatyana61 [14]4 years ago
8 0

Answer:

Semiconductor. sorry i'm late

Explanation:

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If two children, with masses of 16 kg and 24 kg , sit in seats opposite one another, what is the moment of inertia about the rot
Elena-2011 [213]

Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

Mass of one child = 16 kg

Mass of second child = 24 kg

Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.

We need to calculate the moment of inertia

Using formula of moment of inertia

I=I_{1}+I_{2}

I=(m+m_{1})\times r^2+(m+m_{2})\times r^2

m = mass of seat

m₁ =mass of one child

m₂ = mass of second child

r = radius of rod

Put the value into the formula

I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2

I=117.45\ kg-m^2

Hence, The moment of inertia about the rotation axis is 117.45 kg-m²

8 0
3 years ago
A rocket explodes into two fragments, one 25 times heavier than the other. The magnitude of the momentum change of the lighter f
V125BC [204]

Answer:

B) The same as the momentum change of the heavier fragment.

Explanation:

Since the initial momentum of the system is zero, we have

0 = p + p' where p = momentum of lighter fragment = mv where m = mass of lighter fragment, v = velocity of lighter fragment, and p' = momentum of heavier fragment = m'v' where m = mass of heavier fragment = 25m and v = velocity of heavier fragment.

0 = p + p'

p = -p'

Since the initial momentum of each fragment is zero, the momentum change of lighter fragment Δp = final momentum - initial momentum = p - 0  = p

The momentum change of heavier fragment Δp' = final momentum - initial momentum = p' - 0 = p' - 0 = p'

Since p = -p' and Δp = p and Δp' = -p = p ⇒ Δp = Δp'

<u>So, the magnitude of the momentum change of the lighter fragment is the same as that of the heavier fragment.  </u>

So, option B is the answer

4 0
3 years ago
How do you calculate the mass of an object accelerating at22.35m/s2 with a force of 120N
Arte-miy333 [17]

Answer:

The mass of object is calculated as 5.36 kg

Explanation:

The known terms to find the mass are:

           acceleration of object (a) = 22.35 m/s^{2}

                        Force exerted (F) = 120N

                        mass of an object (m) = ?

From Newton's second law of motion;

                                   F = ma

                           or, 120 = m × 22.35

                          or, m= \frac{120}{22.35} kg

                           ∴ m = 5.36 kg

3 0
3 years ago
How is artificial gravity created in spaceships and sattelites ?????? U need some IQ for this
goldfiish [28.3K]

Explanation:

Artificial gravity can be created using a centripetal force. A centripetal force directed towards the center of the turn is required for any object to move in a circular path. In the context of a rotating space station it is the normal force provided by the spacecraft's hull that acts as centripetal force.

Hope it helps.

4 0
3 years ago
Read 2 more answers
PLEASE HELP I HAVE FINALSSS​
vitfil [10]

Answer: 26.67 m/s

Explanation:

Given

Length traveled by the ball s=40\ m

Time taken to reach the goal post is t=3\ s

Initial velocity u=0\ m/s

Using the second equation of motion

\Rightarrow s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0+\frac{1}{2}a(3)^2\\\Rightarrow a=\frac{80}{9}\ m/s^2\\

Now using

\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2\times \frac{80}{9}\times 40\\\\\Rightarrow v=\sqrt{\dfrac{80\times 80}{9}}=\dfrac{80}{3}\\\Rightarrow v=26.67\ m/s

The velocity of ball will be 26.67 m/s

8 0
3 years ago
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