PLS HELP!!!! If u help I will mark brainiest thx
1 answer:
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Answer:
(a) 108
(b) 110.500 kW
(c) 920.84 A
Solution:
As per the question:
Voltage at primary, (rms voltage)
Voltage at secondary, (rms voltage)
Current in the secondary,
Now,
(a) The ratio of secondary to primary turns is given by the relation:
where
= No. of turns in primary
= No. of turns in secondary
≈ 108
(b) The power supplied to the line is given by:
Power, P =
(c) The current rating that the fuse should have is given by: