Answer:
Explanation:
a) 1.00 - 0.12 = 0.88
m = 1200(0.88)^t
b) t = ln(m/1200) / ln(0.88)
c) m = 1200(0.88)^10 = 334.20 g
d) t = ln(10/1200) / ln(0.88) = 37.451... = 37 s
e) t = ln(1/1200) / ln(0.88) = 55.463... = 55 s
Answer:
The answer is 3.48 seconds
Explanation:
The kinematic equation
y= y0+V0*t+1/2*a*(t*t)
-50=0+(0)t+1/2(-9.8)*(t*t)
t=3.194 seconds
During ribbons ball,
x=x0+ Vt+1/2*a*(t*t)
x= 0+(15)*(3.194)+1/2*(0)* (3.194*3.194)
x= 47.9157m
So, distance (D) = 100-47.9157= 52.084m
52.084m=0+15(t)+1/2*(0)(t*t)
t=52.084/15=3.472286= 3.48seconds
Answer:
c. 981 watts

Explanation:
Given:
- horizontal speed of treadmill,

- weight carried,

- grade of the treadmill,

<u>Now the power can be given by:</u>

(where grade is the rise of the front edge per 100 m of the horizontal length)

Answer:
The induced emf between two end is
V
Explanation:
Given:
Length of rod
m
Height
m
Magnetic field
T
For finding induced emf,

Where
velocity of rod,
For finding the velocity of rod.
From kinematics equation,

Where
initial velocity, 



Put the velocity in above equation,

V
Therefore, the induced emf between two end is
V
950kg. It is W=mg. therefore, mass= W/g which is W/10
=9500/10
=950