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lakkis [162]
3 years ago
7

What is the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure? As air

pressure in an area increases, the density of the gas particles in that area decreases. As air pressure in an area increases, the density of the gas particles in that area increases. As air pressure in an area increases, the density of the gas particles in that area remains constant. As air pressure in an area increases, the density of the gas particles in that area increases and decreases in an alternating pattern.
Chemistry
1 answer:
Marina86 [1]3 years ago
3 0

We need to know the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure.

The relationship is: As air pressure in an area increases, the density of the gas particles in that area increases.

For any gaseous substance, density of gas is directly proportional to pressure of gas.

This can be explained from idial gas edquation:

PV=nRT

PV=\frac{w}{M}RT [where, w= mass of substance, M=molar mass of substance]

PM=\frac{w}{V}RT

PM=dRT [where, d=density of thesubstance]

So, for a particular gaseous substance (whose molar mass is known), at particular temperature, pressure is directly related to density of gaseous substance.

Therefore, as air pressure in an area increases, the density of the gas particles in that area increases.

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What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?
Julli [10]

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

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3.1 Copper is a transition
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Maria owns a bakery and bakes many different types of yeast breads. One day she notices that the bread she baked is flat and doe
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The amount of energy in the bonds of the reactants plus any energy absorbed equals the amount of energy in the bonds of the prod
Vinvika [58]
The amount of energy in the bonds of the reactants plus any energy absorbed equals the amount of energy in the bonds of the products plus any energy <span>given off when the products are formed.

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4 0
3 years ago
Read 2 more answers
Compared to a solution with a ph of 6, the hydronium ion concentration of a solution with a Ph of 4 has how many more times the
Alexxx [7]

Answer: The hydronium ion concentration of a solution with a pH of 4 is 100 times more than the the hydronium ion concentration of a solution with a pH of 6

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

1. Solution with pH of 6

6=-\log [H^+]

[H^+]=10^{-6}

2. Solution with pH of 4

4=-\log [H^+]

[H^+]=10^{-4}

\frac{H^+_4}{H^+_6}=\frac{10^{-4}}{10^{-6}}=10^{2}={100}

{H^+_4}=100\times {H^+_6}

Thus the hydronium ion concentration of a solution with a pH of 4 is 100 times more than the the hydronium ion concentration of a solution with a pH of 6

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3 years ago
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