Answer:
C
Explanation:
The substance would be classified as neutral, so C.
Answer:
klklklkllkllklkklkllkl
Explanation:
Cuz thats what you said.. and why not :)
Yup go this website for more information http://dwb.unl.edu/calculators/activities/BalEqn.html
Since we are told that 1L of air contains 0.21L of oxygen, you can use the conversion (0.21L O₂)/(1L air). That means that you can just multiply 6.0L by 0.21L to get 1.26L of O₂.
that means that the lungs can hold about 1.26L of oxygen.
I hope this helps. Let me know if anything is unclear.
Answer:
54.72 g
Explanation:
Mass = ?
Volume = 5.61 L
Pressure = 5.66 atm
Temperature = 311 K
The relationship between these equations is given by the ideal gas equation;
PV = nRT
where R = gas constant = 0.0821 atm L K-1 mol-1
n = PV / RT
n = 5.66 * 5.61 / (0.0821 * 311 )
n = 1.2436 mol
Number of moles = Mass / Molar mass
Mass = Number of moles * Molar mass = 1.2436 * 44 = 54.72 g
